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polet [3.4K]
3 years ago
11

15. All of the following parameters are forces except

Physics
1 answer:
icang [17]3 years ago
3 0

Answer: What do you need help with?

Explanation:

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Compare the results of applying the acceleration equation in the following 2 cases : (1) an object that goes from 0 to 10 m/s in
erastovalidia [21]

2oeuhehdhfhdhfhdjdjdndndjjfjdjfjgfjfjjrjrj

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3 years ago
Which federal agency protects ecosystems and supervisors public access the forests
Rainbow [258]

Answer:

United States forest service

3 0
3 years ago
Read 2 more answers
If The density of this stainless steel is7.85 g/cm3,specific heatis 0.5 J/g.K, melting pointis 1673K, heat of fusion s0.260J/kg.
kodGreya [7K]

Answer:

\Delta H=687.4 J

Explanation:

Hello!

In this case, for this melting process, we can identify two sub-processes in order to take the stainless steel from solid to liquid:

1. Heat up from 298.15 K to 1673 K.

2. Undergo the phase transition.

Both process have an associated enthalpy as shown below:

\Delta H_1=1g*0.5\frac{J}{g*K} (1673K-298.15K)=687.4J

\Delta H_2=0.001kg*\frac{0.260J}{kg} =0.00026J

Therefore, the required heat is:

\Delta H=\Delta H_1+\Delta H_2\\\\\Delta H=687.4J+0.00026J\\\\\Delta H=687.4J

Notice the problem is not providing neither the mass or volume, that is why we assumed the mass is 1 g; however, it can be changed to the mass you are given.

Best regards!

4 0
2 years ago
On the basis of which characteristics jute is considerd as a natural fibre​
klemol [59]

Answer:

Jute is obtained from Jute plant naturally that is why it is considered as a Natural Fibre. It seems golden in color.

6 0
3 years ago
En el País Vasco los deportistas rurales levantan enormes piedras hasta su hombro. En un concurso , Jose levanta una piedra de 2
Mama L [17]

Answer:

Txomin lifted the stone with greater mass. (Txomin levantó la roca con mayor fuerza).

Explanation:

The sportsman that lifts the stone with a greater mass needs a higher force (El deportista que levanta la piedra con mayor masa necesita una mayor fuerza):

José

F = (200\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)

F = 1961.4\,N

Txomin

F = (220\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)

F = 2157.54\,N

Txomin lifted the stone with greater mass. (Txomin levantó la roca con mayor fuerza).

5 0
3 years ago
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