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tiny-mole [99]
3 years ago
10

Is the rate $3.94 for 1 pound considered a unit price Yes or No?

Mathematics
2 answers:
expeople1 [14]3 years ago
5 0
Yes, because a unit price is what you pay for one of many things. A unit rate, if you will.
lisabon 2012 [21]3 years ago
3 0
Hi Jayjaydeking00, 
I know this so I will be trying to help you 
Your answer would be Yes, because a unit price is what you pay for one of many things. A unit rate, if you will.


Hope This Helps
-Jacie-
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3 years ago
What is the completely factored form of x2 – 16xy + 64y2?
Korolek [52]

Answer:

(x-8y)(x-8y) or (x-8y)^2

5 0
3 years ago
Read 2 more answers
See image attached below keeeeeeeeeeeeeeeeeeeed
emmasim [6.3K]

Answer:

.13%

68.26%

2.28%

47.72%

49.87%

34.13%

Step-by-step explanation:

1.) standardize by subtracting the mean and dividng by the standard deviation

(625-1000)/125= -3

go to a ztable to get .0013 or (1-.9987)

this is equal to .13%

2.)

875<x<1125

standardize both seperately and subtract them

(875-1000)/125= -1  whose probability is .1587 (or 1-.8413)

(1125-1000)/125= 1  whose probability is .8413

.8413-.1587= 68.26%

3.)

Find the probability that someone paid less than 1250 and take its compliment

(1250-1000)/125= 2 which has a probability of .9772

take its compliment (1-.9772)= .0228= 2.28%

4.)

Same process as question 2

(750-1000)/125= -2 which has a probability of (1-.9772) = .0228

(1000-1000)/125= 0 which has a probability of .5

.5-.0228= .4772= 47.72%

5.) same deal as the previous question

(625-1000)/125= -3 which has a probability of (1-.9987)= .0013

(1000-1000)/125= 0 which has a probability of .5

.5-.0013= .4987= 49.87%

6.)same deal the previous question

(875-1000)/125= -1 which has a probability of (1-.8413)=.1587

(1000-1000)/125= 0 which has a probability of .5

.5-.1587= .3413= 34.13%

4 0
2 years ago
Find the product (3a2 - 3b) (2a2 - b)
Natasha2012 [34]
(3a^2 - 3b)(2a^2 - b)

3a^2(2a^2 - b) - 3b(2a^2 - b) =
6a^4 - 3a^2b - 6a^2b + 3b^2 =
6a^4 -9a^2b + 3b^2 <===
4 0
3 years ago
SUPER HARD QUESTION (I POSTED THE DIAGRAM) In the diagram of.....
Kisachek [45]

Answer:

A

Step-by-step explanation:

Since m∠JOK is 1/5th of the measure of the full circle (we know this because 72° is 1/5th of 360° and 360° is the measure of the whole circle), we know that the measure of minor arc JK will be 1/5th of the circumference of the circle. C = 2πr and we know that r = 5 so the circumference is 10π. 1/5th of that is 2π.

6 0
2 years ago
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