Answer: 0.7257
Step-by-step explanation:
Given : The weights of steers in a herd are distributed normally.
Standard deviation : 
Let x be the weight of the randomly selected steer .
Z-score : 
The the probability that the weight of a randomly selected steer is greater than 920 lbs using standardized normal distribution table :
Hence, the probability that the weight of a randomly selected steer is greater than 920lbs =0.7257
Step-by-step explanation:
A, B, and C have the same area. So P(A) = 1/3 and P(B) = 1/3, which means P(A or B) = 2/3.
P(success) = 2/3 and P(failure) = 1/3.
The probability of 2 failures is:
P = (1/3)² = 1/9
The probability of 2 successes is:
P = (2/3)²= 4/9
The probability of 1 success and 1 failure can be found either with binomial probability, or simply by subtracting the probabilities we found earlier from 1.
P = 1 - 1/9 - 4/9
P = 4/9
So the answer is the one in the bottom left corner.
A is a 5th degree polynomial.
Okay so this is very easy so basically count the value of each coin then subtract to get *gets a call* hello? *other person starts talking* I just want you to know that the answer is 4 *hangs up* *starts talking* that was weird anyways the answer is four give
