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Tanya [424]
4 years ago
10

How to integrate 7 with respect to x? (Form 5 AddMaths Chapter 3)

Mathematics
1 answer:
8090 [49]4 years ago
4 0

Answer: Go to Wolfram Alpha and type in Integrate sin(x) dx or whatever.


Step-by-step explanation:


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Will a 9/32 inch diameter pin fit into a reamed hole with a diameter of 0.278 inch? (Do not round off your answer and express it
ollegr [7]

Answer:

9/32 inch diameter pin will not fit into a reamed hole with a diameter of 0.278 inch

Step-by-step explanation:

Diameter of reamed hole = 0.278 inch

Radius of reamed hole = \frac{0.278}{2} =0.139

Surface area of reamed hole = \pi r^2

Surface area of reamed hole = 3.14 \times  (0.139)^2

Surface area of reamed hole = 0.06066794

Diameter of pin = \frac{9}{32}

Radius of pin =\frac{9}{64}

Surface area of pin = \pi r^2 = 3.14 \times ( \frac{9}{64})^2=0.0620

Since the surface area of pin is more than the surface area of hole .

So, a 9/32 inch diameter pin will not fit into a reamed hole with a diameter of 0.278 inch

7 0
4 years ago
F Can anyone explain how too find the inverse of the function of this problem? f(x)= (x + 2)3.
Firlakuza [10]
The inverse function is f^-1 (x)= -2+(x/3) dont add the parenethese though, i used the parenethese to show that its x over 3. hope that helped! :D 
5 0
3 years ago
A tank has capacity 6 L and initially contains 11 mg of salt dissolved in 3 L of water. A solution containing 1 mg/L of salt ent
BlackZzzverrR [31]

Answer:

The answer is below

Step-by-step explanation:

a) The maximum capacity of he tank is 6 L and initially it contains 11 mg of salt dissolved in 3 L of water. Solution enters the tank at a rate of 3 L/hr, therefore in x hours, the amount of water that have entered the tank = 3x.

Solution also leaves the tank at a rate of 2L/hr, therefore in x hours, the amount of water that have left the tank = 2x

Hence the amount of water present in the tank at x hours is given as:

3 + 3x - 2x = 3 + x

The time taken to full the tank can be gotten from:

3 + x = 6

x = 6 - 3

x = 3 hr

b)

\frac{dQ}{dx}=3-\frac{2Q}{3+x}\\  \\\frac{dQ}{dx}+\frac{2Q}{3+x}=3\\\\let\ u'=\frac{2u}{3+x}\\\\\frac{u'}{u}=\frac{2Q}{3+x}\\\\ln(u)=2ln(3+x)\\\\u=(3+x)^2\\\\(3+x)^2Q]'=3(3+x)^2\\\\(3+x)^2Q=(3+x)^3+c\\\\Q(0)=11\\\\(3+0)^2(11)=(3+0)^3+c\\\\x=72\\\\Q=x+3+\frac{72}{(x+3)^2}\\ \\Q(3)=3+3+\frac{72}{(3+3)^2}=8\ mg

8 mg/ 6 L = 4/3 mg/L

8 0
3 years ago
Can someone help me with this question, please. The problem is attached.
fomenos

It is a reflection across the y axis, then a translation to the right 2 units.  


I hope this helps!  If you have more you want help with I can help.  

3 0
3 years ago
Members of Alachua District Choir were asked, when given the choice between Romanticism or Gothic
zalisa [80]

Answer:

\begin{array}{cccc}{} & {Romanticism} & {Gothic} & {Total} & {Males} & {48} & {63} & {111}& {Females} & {59} & {62} & {121} & {Total} & {107} & {125} & {232} \ \end{array}

Step-by-step explanation:

Given

Romanticism

Male = 48

Female = 59

Gothic

Male = 63

Female = 62

Required

Complete the table <em>(See attachment for complete question)</em>

The table can be represented as:

\begin{array}{cccc}{} & {Romanticism} & {Gothic} & {Total} & {Males} & {48} & {63} & {111}& {Females} & {59} & {62} & {121} & {Total} & {107} & {125} & {232} \ \end{array}

The "total" column represents the number of males and female sampled, respectively.

Male = 48 + 63 = 111

Female = 59 + 62 = 121

The "total" row represents the number of Romanticism and Gothic sampled, respectively.

Romanticism = 48 + 59 = 107

Gothic = 63 + 62 = 125

The overall sample is calculated by adding up the number of males and females or the number of Romanticism and Gothic

Overall = Male + Female

Overall = 111 + 121 = 232

or

Overall = Romanticism + Gothic

Overall = 107 + 125 = 232

7 0
3 years ago
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