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This is a typical radioactive decay problem which uses the general form:
A = A0e^(-kt)
So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:
A = 192e^(-0.015*55)
<em>A = 84 mg</em>
Answer:
16
Step-by-step explanation:
4+4+4+4
or
8+8
Answer:
Time required to save 1000$ is 100 hours
Step-by-step explanation:
Money wasted = 1000$
savings = 10.00$ per hour
using unitary method
if i am saving 10.00 $ per hour then let in t hours i save 1000$
⇒ 10.00 x t = 1000
dividing above equation by 10 we get,
⇒ t = 100 hours
Therefore, Time required to save 1000$ is 100 hours
