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maria [59]
3 years ago
11

If he changed would you ever get back with him I think he truly means what he says he’s really hurt and always says he feels the

pain that you felt I FaceTime him a lot during the day and he’s always talking and crying over you what do you think he could to ever get you back I want him to be happy I feel like he could really be something that you would like and love

Mathematics
1 answer:
alukav5142 [94]3 years ago
5 0
The answer is D. Angles 2 and 3
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B is the midpoint of line segment AC. Find the measure of line segment AC. *25427084
iris [78.8K]

Answer:

84 units

Explanation:

If B is the midpoint of line AC, then B divides AC into two equal parts (AB and BC).

Therefore:

AB=BC

2x-8=x+17

2x-x=17+8

x=25

Therefore, the measure of the line segment AC

=2(2x-8)

=2(2(25)-8)

=2(50-8)

=2(42)

AC=84 units

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1 year ago
What goes into the square root of 96?
VladimirAG [237]
Hi there, the factors of 96 are 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, and 96. So, we want the highest factor of 96. The factor we will use is the number 16. Lets get solving. √96=√16*6=√16*√6=4√6, Therefore, the square root of 96 simplified is 4√6 and the square root of 96 is 9.79795897113
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3 years ago
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Function p is in the form y = ax2 + c. If the values of a and c are both less than 0,
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where is the graph??????????????

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Which equation is equivalent to
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4 years ago
he number of surface flaws in plastic panels used in the interior of automobiles has a Poisson distribution with a mean of 0.02
Yakvenalex [24]

Answer:

a) 98.01%

b) 13.53\%

c) 27.06%

Step-by-step explanation:

Since a car has 10 square feet of plastic panel, the expected value (mean) for a car to have one flaw is 10*0.02 = 0.2  

If we call P(k) the probability that a car has k flaws then, as P follows a Poisson distribution with mean 0.2,

P(k)= \frac{0.2^ke^{-0.2}}{k!}

a)

In this case, we are looking for P(0)

P(0)= \frac{0.2^0e^{-0.2}}{0!}=e^{-0.2}=0.9801=98.01\%

So, the probability that a car has no flaws is 98.01%

b)

Ten cars have 100 square feet of plastic panel, so now the mean is 100*0.02 = 2 flaws every ten cars.

Now P(k) is the probability that 10 cars have k flaws and  

P(k)= \frac{2^ke^{-2}}{k!}

and  

P(0)= \frac{2^0e^{-2}}{0!}=0.1353=13.53\%

And the probability that 10 cars have no flaws is 13.53%

c)

Here, we are looking for P(1) with P defined as in b)

P(1)= \frac{2^1e^{-2}}{1!}=2e^{-2}=0.2706=27.06\%

Hence, the probability that at most one car has no flaws is 27.06%

6 0
3 years ago
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