Answer:
the answer is 4 (option C)
Step-by-step explanation:
Since the triangles are similar, and in triangle UTV both sides are equal, we can consider QTR also has two equal sides.
therefore, the equation forms:
13x + 3 = 55
13x = 55 - 3
13x = 52
x = 52/13
x = 4
Each of the triangles are equal in base length, height, and area. Remember the formula for the area of a triangle. The area of any triangle is 1/2 times the length of the base (which, in the polygon, is the length of a side) multiplied by the height (which is the same as the apothem in regular polygon)
Answer:
The line segments AA' and BB' are parallel and congruent
Step-by-step explanation:
1. Convert percent into decimal (it will help)
2. Convert Decimal to fraction
The question is:
Check whether the function:
y = [cos(2x)]/x
is a solution of
xy' + y = -2sin(2x)
with the initial condition y(π/4) = 0
Answer:
To check if the function y = [cos(2x)]/x is a solution of the differential equation xy' + y = -2sin(2x), we need to substitute the value of y and the value of the derivative of y on the left hand side of the differential equation and see if we obtain the right hand side of the equation.
Let us do that.
y = [cos(2x)]/x
y' = (-1/x²) [cos(2x)] - (2/x) [sin(2x)]
Now,
xy' + y = x{(-1/x²) [cos(2x)] - (2/x) [sin(2x)]} + ([cos(2x)]/x
= (-1/x)cos(2x) - 2sin(2x) + (1/x)cos(2x)
= -2sin(2x)
Which is the right hand side of the differential equation.
Hence, y is a solution to the differential equation.
