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3 years ago

What would you have to invest today at 5% interest compounded monthly if you wish to have $20,000 in 10 years?

1 answer:

8 0

Simple intrest:-
Intrest(20000)=(Investment(Unknown so lets say Y)xPercent(5%)xtime(10))/100
=
20000=(Yx5%x10)/100 =
5/100x10=
0.5Y/100x100=20000x100/0.5 Y=4000000

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Write the slope-intercept form of the equation of each line. X-3y=6

Alecsey [184]

<span>x -3y=6
3y = x - 6
y = x/3 - 2

answer
</span>slope-intercept form of the equation: y = x/3 - 2

4 0

3 years ago

A rectangular shoebox has a volume of 728 cubic inches. The base of the shoebox measures 8 inches by 6.5 inches. How long is the

bagirrra123 [75]

Divide the volume by the two measures. 728 ÷ 8 = 91 ÷ 6.5 = 14 so, the shoe box is we inches long.

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2 years ago

#10 using right angle below find the tangent of angle A.

just olya [345]

Answer: the first option is the correct answer.

Step-by-step explanation:

Triangle ABC is a right angle triangle.

From the given right angle triangle,

AB represents the hypotenuse of the right angle triangle.

With m∠A as the reference angle,

AC represents the adjacent side of the right angle triangle.

BC represents the opposite side of the right angle triangle.

To determine the tangent of angle A, we would apply the Tangent trigonometric ratio. It is expressed as

Tan θ, = opposite side/adjacent side. Therefore,

Tan A = 5/5√3 = 1/√3

Rationalizing the surd, it becomes

1/√3 × √3/√3

Tan A = √3/3

6 0

2 years ago

The scores of students on the ACT college entrance exam in a recent year had the normal distribution with mean  =18.6 and stand

Maurinko [17]

Answer:

a) 33% probability that a single student randomly chosen from all those taking the test scores 21 or higher.

b) 0.39% probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 18.6, \sigma = 5.9$

a) What is the probability that a single student randomly chosen from all those taking the test scores 21 or higher?

This is 1 subtracted by the pvalue of Z when X = 21. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{21 - 18.6}{5.4}$

$Z = 0.44$

$Z = 0.44$ has a pvalue of 0.67

1 - 0.67 = 0.33

33% probability that a single student randomly chosen from all those taking the test scores 21 or higher.

b) The average score of the 76 students at Northside High who took the test was x =20.4. What is the probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher?

Now we have $n = 76, s = \frac{5.9}{\sqrt{76}} = 0.6768$

This probability is 1 subtracted by the pvalue of Z when X = 20.4. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{20.4 - 18.6}{0.6768}$

$Z = 2.66$

$Z = 2.66$ has a pvalue of 0.9961

1 - 0.9961 = 0.0039

0.39% probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher

4 0

2 years ago

What is the domain of ƒ(x) if ƒ(x) = 1 x – 4?

Alina [70]

The domain would negative infinity to positive infinity . Domain would be the smallest through the largest possibly value of X. If you also need the range it’s ( -4,infinity]

3 0

3 years ago