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irakobra [83]
3 years ago
14

Find the pattern 75,64,53...

Mathematics
2 answers:
timama [110]3 years ago
8 0
Your subtracting 11 for each 76-11=64 ,64-11=53
Anuta_ua [19.1K]3 years ago
3 0
The pattern in -11.
Hope this helps! :)
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PLEASE HELP ME <br>Multiply the monomials: <br><br>a2x5b, −0.6axb2 and 0.6a2b3
Tanzania [10]

Answer:

-0.36 a^{5}b^{6} x^{6}

Step-by-step explanation:

Given:

a^2x^5b,,\ -0.6axb^2,\ and\ 0.6a^2b^3

Required

Multiply

The above can be written as

a^2x^5b * -0.6axb^2\ * \ 0.6a^2b^3

Split the above expression

a^2*x^5*b * -0.6*a*x*b^2\ * \ 0.6*a^2*b^3

Collect like terms

-0.6 * 0.6 * a^2*a*a^2*b *b^2 *b^3*x^5*x

Apply first law on indices

-0.36  * a^{2+1+2} *b^{1+2+3} *x^{5+1}

-0.36  * a^{5} *b^{6} *x^{6}

-0.36 a^{5}b^{6} x^{6}

Hence, a^2x^5b * -0.6axb^2\ * \ 0.6a^2b^3 is equivalent to -0.36 a^{5}b^{6} x^{6}

8 0
3 years ago
Can someone help me with this question ? Show steps please
jek_recluse [69]

Answer:

B) \boxed{A_T=108\;in^2}

Step-by-step explanation:

That is a triangular prism and thus, it has two bases that are triangles, in this case, right triangles, whose hypotenuse is 5 in. long and one of its legs is 4 in. and the other one, 3 in.

The first step is to find the area of both bases like this:

A_B=2\left(\dfrac{b\cdot h}{2}\right)=b\cdot h=4\cdot 3\\\\ \boxed{A_B=12\;in^2}

The second step is to get the lateral area, which is compound of three rectangles, hence the process is the following:

A_L=b_1\cdot h_1+b_2\cdot h_2+b_3\cdot h_3\\A_L=8\cdot3+8\cdot4+8\cdot5\\A_L=24+32+40\\\boxed{A_L=96\;in^2}

Finally, we sum both of the areas found to calculate the total area.

A_T=A_B+A_L\\A_T=12+96\\\boxed{A_T=108\;in^2}

So, the answer is option B).

4 0
3 years ago
The lengths of three sides of a quadrilateral are shown below:
julsineya [31]
Answers: 
Part A: 12y² + 10y – 21
Part B: 4y³ + 6y² + 6y – 5 
Part C: See below.

Explanations: 
Part A: 
For this part, you add Sides 1, 2 and 3 together by combining like terms:
Side 1 = 3y² + 2y – 6
Side 2 = 4y² + 3y – 7
Side 3 = 5y² + 5y – 8
3y² + 2y – 6 + 4y² + 3y – 7 + 5y² + 5y – 8
Combine like terms: 
3y² + 4y² + 5y² + 2y + 3y + 5y – 6 – 7 – 8 
12y² + 10y – 21

Part B: 
You have the total perimeter and the sum of three of the sides, so you just need that fourth side value, which we can call d.
P = 4y³ + 18y² + 16y – 26
Sides 1, 2 & 3 = 12y² + 10y – 21 
Create an algebraic expression: 
12y² + 10y – 21 + d = 4y³ + 18y² + 16y – 26
Solve for d: 
12y² + 10y – 21 + d = 4y³ + 18y² + 16y – 26
– 12y²                                – 12y²
10y – 21 + d = 4y³ + 6y² + 16y – 26 
– 10y                               – 10y
– 21 + d = 4y³ + 6y² + 6y – 26 
+ 21                                + 21 
d = 4y³ + 6y² + 6y – 5 

Part C: 
If closed means that the degree that these polynomials are at stay that way, then yes, this is true in these cases because you will notice that each side had a y², y and no coefficient value except for the fourth one. This didn't change, because you only add and subtract like terms.
7 0
3 years ago
Find X using the Pythagorean Theorem
Natalija [7]

Answer:

x = 4.47

Step-by-step explanation:

Formula for hypotenuse:

x =\sqrt{a^2+b^2}

x=\sqrt{4^2+2^2}

x=\sqrt{16+4}

x=\sqrt{20}

x=4.47

8 0
3 years ago
Help me please this will help my grade !
Leni [432]

Answer:

Point D

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
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