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sasho [114]
3 years ago
9

PLEASE HELP ME Multiply the monomials: a2x5b, −0.6axb2 and 0.6a2b3

Mathematics
1 answer:
Tanzania [10]3 years ago
8 0

Answer:

-0.36 a^{5}b^{6} x^{6}

Step-by-step explanation:

Given:

a^2x^5b,,\ -0.6axb^2,\ and\ 0.6a^2b^3

Required

Multiply

The above can be written as

a^2x^5b * -0.6axb^2\ * \ 0.6a^2b^3

Split the above expression

a^2*x^5*b * -0.6*a*x*b^2\ * \ 0.6*a^2*b^3

Collect like terms

-0.6 * 0.6 * a^2*a*a^2*b *b^2 *b^3*x^5*x

Apply first law on indices

-0.36  * a^{2+1+2} *b^{1+2+3} *x^{5+1}

-0.36  * a^{5} *b^{6} *x^{6}

-0.36 a^{5}b^{6} x^{6}

Hence, a^2x^5b * -0.6axb^2\ * \ 0.6a^2b^3 is equivalent to -0.36 a^{5}b^{6} x^{6}

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Step-by-step explanation:

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Leona [35]

Given:

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To find:

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