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Afina-wow [57]
2 years ago
8

A consultant needs to make at least $600 this week. She earns $120 for each

Mathematics
2 answers:
vodka [1.7K]2 years ago
7 0
The answer is A, She need to make equal to or more than 600 so that <_600 and since there each behind 120 an 60 they both have variables
Readme [11.4K]2 years ago
6 0

ABCDEFG h i j k l m n o p q r s t u v w x y z

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Integrate cosx/sqrt(1+cosx)dx
Step2247 [10]
<span>Take the integral: integral (cos(x))/sqrt(cos(x)+1) dx
For the integrand (cos(x))/sqrt(1+cos(x)), substitute u = 1+cos(x) and du = -sin(x) dx: = integral (u-1)/(sqrt(2-u) u) du
For the integrand (-1+u)/(sqrt(2-u) u), substitute s = sqrt(2-u) and ds = -1/(2 sqrt(2-u)) du: = integral -(2 (1-s^2))/(2-s^2) ds
Factor out constants: = -2 integral (1-s^2)/(2-s^2) ds
For the integrand (1-s^2)/(2-s^2), cancel common terms in the numerator and denominator: = -2 integral (s^2-1)/(s^2-2) ds
For the integrand (-1+s^2)/(-2+s^2), do long division: = -2 integral (1/(s^2-2)+1) ds
Integrate the sum term by term: = -2 integral 1/(s^2-2) ds-2 integral 1 ds
Factor -2 from the denominator: = -2 integral -1/(2 (1-s^2/2)) ds-2 integral 1 ds
Factor out constants: = integral 1/(1-s^2/2) ds-2 integral 1 ds
For the integrand 1/(1-s^2/2), substitute p = s/sqrt(2) and dp = 1/sqrt(2) ds: = sqrt(2) integral 1/(1-p^2) dp-2 integral 1 ds
The integral of 1/(1-p^2) is tanh^(-1)(p): = sqrt(2) tanh^(-1)(p)-2 integral 1 ds
The integral of 1 is s: = sqrt(2) tanh^(-1)(p)-2 s+constant
Substitute back for p = s/sqrt(2): = sqrt(2) tanh^(-1)(s/sqrt(2))-2 s+constant
Substitute back for s = sqrt(2-u): = sqrt(2) tanh^(-1)(sqrt(1-u/2))-2 sqrt(2-u)+constant
Substitute back for u = 1+cos(x): = sqrt(2) tanh^(-1)(sqrt(sin^2(x/2)))-2 sqrt(1-cos(x))+constant
Factor the answer a different way: = sqrt(1-cos(x)) (csc(x/2) tanh^(-1)(sin(x/2))-2)+constant
Which is equivalent for restricted x values to:
Answer: | | = (2 cos(x/2) (2 sin(x/2)+log(cos(x/4)-sin(x/4))-log(sin(x/4)+cos(x/4))))/sqrt(cos(x)+1)+constant</span>
3 0
3 years ago
Between which two integers does √700 lie?
erastovalidia [21]
The square root of 700 is about 26.45, so it lies between 26 and 27
4 0
3 years ago
Read 2 more answers
One number is 6 more than another. Twice the larger number is 5 times the smaller.
tresset_1 [31]

Answer:

The smaller number is 4

Step-by-step explanation:

Larger number = x

Smaller number = y

Write 2 equations

y + 6 = x

2x = 5y

Substitute x in the first equation to the second equation

2(y + 6) = 5y

Multiply 2(y + 6)

2y + 12 = 5y

Subtract 2y from both sides of the equation

12 = 3y

Divide both sides of the equation by 3

y = 4

x = y + 6 = 4 + 6 = 10

The smaller number is 4

Hope this helps :)

3 0
3 years ago
Mr. And Mrs ikan deposited $15,000 into college savings accounts with an annual compound interest rate 5.25% when their daughter
m_a_m_a [10]

Answer:

$37,650

Step-by-step explanation:

A=15000(1+0.0525)^18

A=15000(2.51)

A=37650

8 0
3 years ago
A (x+y)-x (a+b) what is the answer please
ra1l [238]
The answer would be ay-xb
5 0
3 years ago
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