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xenn [34]
3 years ago
14

Raymond spends 1/10 of his vacation budget on a car rental. Write an expression for how much Raymond has to spend on the rest of

his vacation. If he budgets $650 for the vacation, how much will he have left to spend?
A. (1/10) b,$65

B. (9/10) b,$65

C. (9/10) b, $585

D. (1/10) b,$585
Mathematics
2 answers:
patriot [66]3 years ago
7 0

Answer:

C

Step-by-step explanation:

1/10 of 650 is 65, so 585 is 9/10. 9/10 is what he has left.

Greeley [361]3 years ago
6 0

Answer:

C

Step-by-step explanation:

1/10th of 650 is 65. then, do 650 - 65. 9/10th of 650 is 585, so the answer to this question is C.

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Which triangles can not be proved congruent?#37
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3 years ago
For parts a and bâ, use technology to estimate the following. âa) The critical value of t for a 90â% confidence interval with df
rjkz [21]

Answer:

a) For the 90% confidence interval the value of \alpha=1-0.9=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:

t_{\alpha/2} =\pm 2.35

b) For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:

t_{\alpha/2} =\pm 2.62

Step-by-step explanation:

Previous concepts

The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".

The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.  

The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."

Solution to the problem

Part a

For the 90% confidence interval the value of \alpha=1-0.9=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:

t_{\alpha/2} =\pm 2.35

Part b

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:

t_{\alpha/2} =\pm 2.62

3 0
3 years ago
A number is not an integer what type of number can it be
MrRa [10]
It can be a decimal or fraction. An integer HAS to be a whole number.
-2, 10, and 4300 are integers
8.4, -0.14568, and 1/2 are not integers
8 0
3 years ago
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