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4vir4ik [10]
3 years ago
5

The length of a rectangle is 4 less than twice the width. If the perimeter of the rectangle is 130, find the length of the recta

ngle.
Mathematics
1 answer:
Alchen [17]3 years ago
4 0

Answer:

Let L be the length of the rectangle and w be the width of the rectangle.

"The lenght of a rectangle is one less than twice the width" means L=2W-1

Using perimeter formula of a rectangle which is P=2(L+W) you have:

P=2(L+W)

130=2(2W-1+W)

Solve equation above to find W

130=2(3W-1)

130=6W-2

130+2=6W

132=6W

W=22

From here you find L=2W-1=2x22-1=43

Only thing left is to find area A=LxW

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Answer:

The dimensions of the pool are:

Width: 8.944 feet

Length: 17.888 feet

Step-by-step explanation:

From Geometry, the area of a rectangle (A), measured in square feet, is determined by the following equations:

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If we know that w = x, l = 2\cdot x and A = 160\,ft^{2}, then we get the following second order polynomial:

2\cdot x^{2}-160 = 0 (1)

And we solve the expression for x:

2\cdot x^{2} = 160

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x = \sqrt{80}\,ft

x \approx 8.944\,ft

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2 years ago
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Oksanka [162]

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Options (3) and (6)

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Geometrically we denote them with an arrow over the line.

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6 0
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