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snow_tiger [21]
3 years ago
7

Which is a feature of a single replacement reaction?

Chemistry
2 answers:
Natali5045456 [20]3 years ago
7 0

Answer:

Substance G reacts with compound XY to form GY and X.

Explanation:

Vika [28.1K]3 years ago
4 0

Answer: B: Substance G reacts with compound XY to form GY and X.

Just took quiz.

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SO2 reacts with O2 to produce SO3. If 86.0 g of SO2 is placed in a reaction vessel along with excess oxygen gas, how many moles
Salsk061 [2.6K]

Answer:

0,72 moles of SO₂ remain

Explanation:

The reaction is:

2SO₂ + O₂ → 2SO₃

Where molecular mass of SO₂ is 64,066g/mol and of SO₃ is 80,066g/mol.

86,0g of SO₂ are:

86,0g × (1mol / 64,066g) = <em>1,34 moles of SO₂</em>.

50,0g of SO₃ are:

50,0g × (1mol / 80,066g) = <em>0,62 moles of SO₃</em>.

Now, as 2 moles of SO₂ produce 2 moles of SO₃, the moles of SO₂ that remain after the reaction are the initial moles of SO₂ - moles of SO₃:

1,34 moles - 0,62 moles =

<em>0,72 moles of SO₂ remain</em>

I hope it helps!

7 0
3 years ago
Help needed ASAP
Shalnov [3]

Natural selection cannot work if beneficial traits are not hereditary

5 0
3 years ago
Read 2 more answers
When 10.0 grams of ch4 reacts completely with 40.0 grams of o2 such that there are no reactants left over, 27.5 grams of carbon
Zina [86]

The balanced equation for the reaction is :-

CH₄(g) + 2O₂(g)  ---------> CO₂(g) + 2H₂O(l)

Molar mass of CH₄ = 16 g/mole

Molar mass of O₂ = 32 g/mole

Molar mass of H₂O = 18 g/mole

Molar mass of CO₂ = 44 g/mole

Now we calculate the number of moles of reactants,

moles of CH₄ = mass of CH₄/molar mass of CH₄ = 10/16 = 0.625

Moles of O₂ = mass of O₂/molar mass of O₂ = 40/32 = 1.25

Now, as per the balanced reaction, for complete reaction to occur, one mole of CH₄ require 2 moles of O₂

Thus, 0.625 moles of CH₄ requires 1.25 moles of O₂

both CH₄ and O₂ are present in the exact required quantity.

Hence, moles of CO₂ formed = moles of CH₄ reacted = 0.625

Mass of CO₂ formed = moles of CO₂ x Molar mass of CO₂ = 0.625 x 44 = 27.5g

Moles of H₂O formed = moles of O₂ reacted = 1.25g

<span>Thus, mass of H</span>₂O formed = moles of H₂O x molar mass of H₂O = 1.25 x 18 = 22.5g

8 0
3 years ago
How many atoms are in 52.3 g of lithium hypochlorite (LiClO)?​
garri49 [273]

Answer:

1.62 × 10²⁴ atoms are in 52.3 g of lithium hypochlorite.

Explanation:

To find the amount of atoms that are in 52.3 g of lithium hypochlorite, we must first find the amount of moles. We do this by dividing by the molar mass of lithium hypochlorite.

52.3 g ÷ 58.4 g/mol = 0.896 mol

Next we must find the amount of formula units, we do this be multiplying by Avagadro's number.

0.896 mol × 6.02 × 10²³ = 5.39 × 10²³ f.u.

Now to get the amount of atoms we can multiply the amount of formula units by the amout of atoms in one formula unit.

5.39 × 10²³ f.u. × 3 atom/f.u. = 1.62 × 10²⁴ atoms

1.62 × 10²⁴ atoms are in 52.3 g of lithium hypochlorite.

7 0
3 years ago
Which of the following lists contains only
Elena-2011 [213]
The answer to the question is D. Zinc, Gold, Aluminum, and oxygen are all elements in the periodic table
5 0
2 years ago
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