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Varvara68 [4.7K]
3 years ago
10

What type of reactive intermediate is formed in the reaction of propene with n-bromosuccinimide (nbs) to give 3-bromo-1-propene?

Chemistry
1 answer:
Advocard [28]3 years ago
4 0
The type of reactive intermediate that is formed in the reaction of propene with n-bromosuccinimide (nbs) to give 3-bromo-1-propene would be an allylic radical. Having NBS as one of the reactants suggests that a free radical bromination would occur between the reactants. In propene, the methyl group would be attacked since the free radical that is being formed would only stabilize by resonance. An allylic radical is a radical that is resonance-stabilized where each of the resonance forms containing unpaired electrons is on an allylic carbon. It can be classified as a primary, secondary or a tertiary allylic radical depending on where is the allylic carbon.
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2.50 L of a gas at standard temperature and pressure is compressed to 575 mL. What is the new pressure of the gas
vfiekz [6]

Answer:

4.35 atm

Explanation:

According to the information given;

  • Initial volume of the gas, V₁ is 2.50 L
  • Initial pressure of the gas is standard pressure P₁, normally 1 atm
  • New volume of the gas, V₂ is 575 mL

We are required to determine the new pressure of the gas, P₂ ;

To answer the question, we are going to use the Boyle's law, that relates pressure and volume at constant temperature.

According to Boyle's law;

P₁V₁ = P₂V₂

Therefore, to determine the new pressure, P₂, we rearrange the formula;

New pressure, P₂ = P₁V₁ ÷ V₂

Thus;

P₂ = ( 1 atm × 2.50 L) ÷ 0.575 L

    = 4.3478 atm

     = 4.35 atm

Therefore, the new pressure of the gas is 4.35 atm

6 0
3 years ago
Read 2 more answers
How many grams of sulfur trioxide are produced 18 mol O2 react with sufficient sulfur? Show all your work S8 +12O 2> 8SO3
SOVA2 [1]

Answer:

m_{SO_3}=2.31x10^4gSO_3

Explanation:

Hello!

In this case, since the reaction between sulfur and oxygen is:

S_8 +\frac{1}{2} O_2 \rightarrow 8SO_3

Whereas there is a 1/2:8 mole ratio between oxygen and SO3, and we can compute the produced grams of product as shown below:

m_{SO_3}=18molO_2*\frac{8molSO_3}{1/2molO_2} *\frac{80.06gSO_3}{1molSO_3} \\\\m_{SO_3}=23,057.3gSO_3=2.31x10^4gSO_3

Best regards!

7 0
3 years ago
Arrange the eluting power of the listed solvents in normal-phase chromatography. The highest eluting power solvent is number 1;
BabaBlast [244]

Answer:

Explanation:

Part a

Normal Phase Chromatography

In the normal phase chromatography, the eluting power is highest for the solvent which has the highest polarity.

So from the given solvents as Methanol, Dichloromethane and Ethyl Acetate

the relative polarities are given as

Methanol=0.762

Dichloromethane (methylene chloride)=0.309

Ethyl Acetate=0.228

So the numbers are given as

Methanol :1

Dichloromethane (methylene chloride):2

Ethyl Acetate:3

Reverse Phase Chromatography

In the reverse phase chromatography, the eluting power is highest for the solvent which has the lowest polarity.

So from the given solvents as diethyl ether , water and toluene

the relative polarities are given as

Diethyl ether=0.117

Water=1.0

Toluene=0.099

So the alphabets are given as

Toluene :A

Diethyl ether: B

Water:C

3 0
3 years ago
No two units of matter can occupy the same_______ at the same_______ .
riadik2000 [5.3K]
First blank- space
second blank- time
Hope this is extra helpful but also check your notes! have a wonderful day and stay safe is you are up north in the snow!
5 0
4 years ago
Read 2 more answers
Calculate the number of moles when 3.00l of a gas at 814 mmhg and 25 °c?
Mariulka [41]
  • Volume=V=3L
  • Pressure=P=814mmHg
  • Temp=T=25°C

So

No of moles=n

\\ \rm\rightarrowtail PV=nRT

\\ \rm\rightarrowtail n=\dfrac{PV}{RT}

\\ \rm\rightarrowtail n=\dfrac{814(3)}{25R}

\\ \rm\rightarrowtail n=2442/25R

\\ \rm\rightarrowtail n=97.7Rmol

5 0
2 years ago
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