Answer:
2.67 × 10⁻²
Explanation:
Equation for the reaction is expressed as:
CaCrO₄(s) ⇄ Ca₂⁺(aq) + CrO₂⁻⁴(aq)
Given that:
Kc=7.1×10⁻⁴
Kc=
Kc= [x][x]
Kc= [x²]
7.1×10⁻⁴ = [x²]
x =
x = 0.0267
x =
1. 2KCIO3, -- 2KCI + 302 How many moles of O2 will be produced from 2.25 moles of KCIO3?
1 answer:
Answer:
3.375moles of O₂
Explanation:
The reaction expression is given as;
2KClO₃ → 2KCl + 3O₂
Number of moles of KClO₃ = 2.25moles
Now;
To find the number of moles of O₂ produced we use known number of moles.
So;
2 mole of KClO₃ will produce 3 moles of O₂
2.25moles of KClO₃ will produce = 3.375moles of O₂
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Answer:
See below.
Step-by-step explanation:
Ethers react with HI at high temperature to produce an alky halide and an alcohol.
R-OR' + HI ⟶ R-I + H-OR'
<em>Benzylic ethers</em> react by an Sₙ1 mechanism by forming the stable benzyl cation.
- PhCH₂-OR + HI ⟶ PhCH₂-O⁺(H)R + I⁻ Protonation of the ether
- PhCH₂-O⁺(H)R ⟶ PhCH₂⁺ + HOR Sₙ1 ionization of oxonium ion
- PhCH₂⁺ + I⁻ ⟶ PhCH₂-I Nucleophilic attack by I⁻
If there is excess HI, the alcohol formed in Step 2 is also converted to an alkyl iodide:
ROH +HI ⟶ R-I + H-OH
Thus, benzyl ethyl ether reacts to form benzyl iodide (a) and ethanol (b).
The ethanol reacts with excess HI in an Sₙ2 reaction to form ethyl iodide (c).
Neutralization reaction takes place between an acid and a base to form salt and water.
In the given reaction the acid is hydrochloric acid HCl and the base is aluminum hydroxide (Al(OH)).
The correct balanced equation for the neutralization reaction that occurs between aluminum hydroxide and hydrochloric acid can be represented as:
Al(OH)can give 3 hydroxide,
ions which can neutralize the 3
ion produced by 3 HCl molecules giving 3 mole of water and the salt aluminum chloride, AlCl
.
Therefore the correct option will be.
D. Al(OH)3 + 3 HCl (aq) --> AlCl3(aq) + 3 H2O(l)