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Semenov [28]
3 years ago
12

1. 2KCIO3, -- 2KCI + 302 How many moles of O2 will be produced from 2.25 moles of KCIO3?

Chemistry
1 answer:
Scilla [17]3 years ago
8 0

Answer:

3.375moles of O₂

Explanation:

The reaction expression is given as;

                   2KClO₃ → 2KCl + 3O₂

Number of moles of KClO₃  = 2.25moles

Now;

To find the number of moles of O₂ produced we use known number of moles.

So;

                  2 mole of KClO₃ will produce 3 moles of O₂

                 2.25moles of KClO₃ will produce \frac{2.25 x 3}{2}   = 3.375moles of O₂

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Phosphoric acid is a triprotic acid with the following pKa values:pKa1=2.148, pKa2=7.198, pKa3=12.375You wish to prepare 1.000 L
laila [671]

Answer:

NaH₂PO₄ =  1.876 g

Na₂HPO₄ =  4.879 g

Combinations: H₃PO₄ and Na₂HPO₄; H₃PO₄ and Na₃HPO₄

Explanation:

To have a buffer at 7.540, the acid must be in it second ionization, because the buffer capacity is pKa ± 1. So, we must use pKa2 = 7.198

The relation bewteen the acid and its conjugated base (ion), is given by the Henderson–Hasselbalch equation:

pH = pKa + log[A⁻]/[HA], where [A⁻] is the concentration of the conjugated base, and [HA] the concentration of the acid. Then:

7.540 = 7.198 + log[A⁻]/[HA]

log[A⁻]/[HA] = 0.342

[A⁻]/[HA] = 10^{0.342}

[A⁻]/[HA] = 2.198

[A⁻] = 2.198*[HA]

The concentration of the acid and it's conjugated base must be equal to the concentration of the buffer 0.0500 M, so:

[A⁻] + [HA] = 0.0500

2.198*[HA] + [HA] = 0.0500

3.198*[HA] = 0.0500

[HA] = 0.01563 M

[A⁻] = 0.0500 - 0.01563

[A⁻] = 0.03436 M

The mix reaction is

NaH₂PO₄ + Na₂HPO₄ → HPO₄⁻² + 3Na + H₂PO₄⁻

The second ionization is:

H₂PO₄⁻ ⇄ HPO₄⁻² + H⁺

So, H₂PO₄⁻ is the acid form, and its concentration is the same as NaH₂PO₄, and HPO₄⁻² is the conjugated base, and its concentration is the same as Na₂HPO₄ (stoichiometry is 1:1 for both).

So, the number of moles of these salts are:

NaH₂PO₄ = 0.01563 M * 1.000 L = 0.01563 mol

Na₂HPO₄ = 0.03436 M* 1.000 L = 0.03436 mol

The molar masses are, Na: 23 g/mol, H: 1 g/mol, P: 31 g/mol, and O = 16 g/mol, so:

NaH₂PO₄ = 23 + 2*1 + 31 + 4*16 = 120 g/mol

Na₂HPO₄ = 2*23 + 1 + 31 + 4*16 = 142 g/mol

The mass is the number of moles multiplied by the molar mass, so:

NaH₂PO₄ = 0.01563 mol * 120 g/mol = 1.876 g

Na₂HPO₄ = 0.03436 mol * 142 g/mol = 4.879 g

To prepare this buffer, it's necessary to have in solution the species H₂PO₄⁻ and HPO₄⁻², so it can be prepared for mixing the combination of:

H₃PO₄ and Na₂HPO₄ (the acid is triprotic so, it will form the H₂PO₄⁻ , and the salt Na₂HPO₄ will dissociate in Na⁺ and HPO₄²⁻);

H₃PO₄ and Na₃HPO₄ (same reason).

The other combinations will not form the species required.

8 0
3 years ago
You cannot round a number if it has a decimal point true or false
Katyanochek1 [597]
The answer is false. u can still round if # is a decimal
5 0
3 years ago
The electron configuration of an element is shown below.
gayaneshka [121]

Answer:it is in group 7

Explanation:it is in this group because in the increasing number of atomic number the element is found in group seven. The element is likely to receive 3 electrons while bonding with another element to make it stable.

5 0
2 years ago
Read 2 more answers
1. What would happen to the current model of the atom if new information about its structure is discovered in the future?
Semenov [28]
1-Option A. Current model will be revised. 
2-Option D. Nucleus
3-<span>Option B. </span>Counting the no. of protons.
6 0
3 years ago
Select the correct empirical formula for each molecular formula given.
Sauron [17]

Answer:

CH₂O

Explanation:

Empirical formula:

It is the simplest formula gives the ratio of atoms of different elements in small whole number.

Molecular formula:

Molecular formula shows the actual whole number ratio of elements present in compound.

Given molecular formula: C₆H₁₂O₆

Empirical formula = CH₂O

In molecular formula six moles of carbon six moles of oxygen and 12 moles of hydrogen are present.

To get the smallest whole number we divide the each number by 6 and we get CH₂O which is empirical formula of C₆H₁₂O₆.

8 0
3 years ago
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