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Setler [38]
3 years ago
9

1) A jet travels 410 miles in 2 hours. At this rate, how far could the jet fly in

Mathematics
2 answers:
umka2103 [35]3 years ago
8 0

Answer:

2665 miles in 13 hours, the rate is 205 mph.

Step-by-step explanation:

410/2 is 205 mph. 205 mph * 13 hours is 2665 miles.

dimulka [17.4K]3 years ago
3 0
410/2 = 205
205x13=2665
They will travel 2665 miles in 13 hours
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Find the volume of a cone with a height of 12 and a base diameter of 6.
vichka [17]

Answer: 466.56

Step-by-step explanation:

Volume = pi times radius^2 times height/3

Radius = 1/2 of the diameter

Volume = 3.24 times 6^2 times 12/3

Volume = 3.24 times 36 times 4

Volume = 116.64 times 4

Volume = 466.56

5 0
2 years ago
When f(x) = –3, what is x?<br><br> –29<br> –10<br> –3<br> –1
mariarad [96]

Answer:

x = - 1

Step-by-step explanation:

I hope this will help you

6 0
1 year ago
The diagram shows the net of a juice box. The box is a rectangular prism.
Hoochie [10]

Answer:

269.6 square centimeters

Step-by-step explanation:

<u><em>The correct question is</em></u>

The diagram shows the net of a juice box. the box is a rectangular prism. what is the surface area of the juice box? 6.4 cm 4 cm 10.5 cm

we know that

The surface area of a rectangular prism is equal to

SA=2B+PH

where

B is the area of the base

P is the perimeter of the base

H is the height of the prism

we have

L=6.4\ cm\\W=4\ cm\\H=10.5\ cm

<em>Find the area of the base B</em>

B=LW

substitute the given values

B=(6.4)(4)=25.6\ cm^2

<em>Find the perimeter of the base P</em>

P=2(L+W)

substitute the given values

P=2(6.4+4)=20.8\ cm

<em>Find the surface area</em>

SA=2B+PH

substitute  

SA=2(25.6)+(20.8)10.5=269.6\ cm^2

6 0
3 years ago
What is the measure of ∠S?
wolverine [178]

Answer:

30 degrees

Step-by-step explanation:

The angles must add up to 180 degrees and the triangles have the same angles.

8 0
3 years ago
Read 2 more answers
In the pulley system shown in this figure, MQ = 30 mm, NP = 10 mm, and QP = 21 mm. Find MN.
ankoles [38]
<h2>Answer:</h2>

\boxed{\overline{MN}=37.96}

<h2>Step-by-step explanation:</h2>

For a better understanding of this problem, see the figure below. Our goal is to find \overline{MN}. Since:

\angle MRS=\angle MQP=90^{\circ} \\ \\ \overline{MQ}=\overline{MR}=30mm

and \overline{MN} is a common side both for ΔMRN and ΔMQN, then by SAS postulate, these two triangles are congruent and:

\overline{RN}=\overline{QN}

By Pythagorean theorem, for triangle NQP:

\overline{QN}=\sqrt{\overline{NP}^2+\overline{QP}^2} \\ \\ \overline{QN}=\sqrt{10^2+21^2} \\ \\ \overline{QN}=\sqrt{541}

Applying Pythagorean theorem again, but for triangle MQN:

\overline{MN}=\sqrt{\overline{MQ}^2+\overline{QN}^2} \\ \\ \overline{MN}=\sqrt{30^2+(\sqrt{541})^2} \\ \\ \boxed{\overline{MN}=37.96}

3 0
3 years ago
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