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3 years ago

A picture shows the net of the lateral surface of the cone. Which statement about this cone is NOT true?

Mathematics

1 answer:

LuckyWell [14K]3 years ago

4 0

Answer:

Can you include the picture because i don't know which question you are talking about.

Step-by-step explanation:

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What is the vertex of the graph of the function f(x) = x² + 8x - 2?

chubhunter [2.5K]

Answer:

(4, -18)

Step-by-step explanation:

First Use this formula for the x -axis -b/2a

-8/2(1) is -4

Then plug in -4 to the equation

(-4)^2+8(-4)-2 = -18

6 0

2 years ago

The equation for line s can be written as y = x + 3. Line t, which is parallel to line s,

arlik [135]

Answer:

y=x-1

Step-by-step explanation:

6 0

3 years ago

Please help! I'm getting timed.

Molodets [167]

Hi there! The answer is A.

$t = 2(s + 2)$
To get a proper idea of the type of function this formula represents we work out the parenthesis.

Working out the parenthesis can for instance be done using rainbow technique.
$t = 2s + 4$

We can now see sinilarities between this function an the general function of a line in slope intercept form
$y = mx + n$

The function t therefore describes a line with slope 2 and y-intercept 4. Therefore the answer is A.

3 0

3 years ago

There are 50 tickets in a raffle bag, and 10 of the tickets belong to Gary. A ticket is chosen at random, and the ticket owner's

Helga [31]

The probability of it happening once is 1/5, since 10/50 simplifies to 1/5. Because the ticket goes back in the bag, the probability stays constant at 1/5.

For it to happen twice, you multiply the probability of it happening once, twice.

1/5 • 1/5 = 1/25 probability of it being Gary's name twice in a row.

8 0

3 years ago

How to solve logarithmic equations as such

Serga [27]

$\bf \textit{exponential form of a logarithm} \\\\ \log_a b=y \implies a^y= b\qquad\qquad a^y= b\implies \log_a b=y \\\\\\ \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} ~\hspace{7em} \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \log_2(x-1)=\log_8(x^3-2x^2-2x+5) \\\\\\ \log_2(x-1)=\log_{2^3}(x^3-2x^2-2x+5) \\\\\\ \log_{2^3}(x^3-2x^2-2x+5)=\log_2(x-1) \\\\\\ \stackrel{\textit{writing this in exponential notation}}{(2^3)^{\log_2(x-1)}=x^3-2x^2-2x+5}\implies (2)^{3\log_2(x-1)}=x^3-2x^2-2x+5$

$\bf (2)^{\log_2[(x-1)^3]}=x^3-2x^2-2x+5\implies \stackrel{\textit{using the cancellation rule}}{(x-1)^3=x^3-2x^2-2x+5} \\\\\\ \stackrel{\textit{expanding the left-side}}{x^3-3x^2+3x-1}=x^3-2x^2-2x+5\implies 0=x^2-5x+6 \\\\\\ 0=(x-3)(x-2)\implies x= \begin{cases} 3\\ 2 \end{cases}$

5 0

3 years ago