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alekssr [168]
3 years ago
14

2

Mathematics
1 answer:
SpyIntel [72]3 years ago
8 0

Answer:

4,507.2‬

Step-by-step explanaation:

<h2>price started with times the investment rate then times by the years its there for</h2>
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Select all the equations that are true when “x” is (-2).
mina [271]

Answer:

The first one, the third one, and the fourth one.

Step-by-step explanation:

i just put the ones that are correct. If you want me to write out why the incorrect ones are incorrect, let me know.

1.

-6=3x

-6= 3(-2)

-6= -6

3. -8= x+x+x+x

-8= -2+-2+-2+-2

-8= -8

4. x/2= (-1)

-2/2 =(-1)

-1= -1

6 0
3 years ago
What’s the answer to this if u know tho! Thank uuu :)))
alukav5142 [94]

Answer:

180=40+(x+20)

x+20=140

x=120

6 0
3 years ago
Read 2 more answers
The table represents a linear equation.
storchak [24]

Answer:

y – 8 = –0.2(x + 10)

Step-by-step explanation:

4 0
3 years ago
1J
Harlamova29_29 [7]

Answer:

(1,-1)

Step-by-step explanation:

We can solve the system by using substitution.

In order to do this we must make x the subject in the first equation.

We can do this by simply subtract 2y from both sides

x + 2y = -1

subtract 2y from both sides

x + 2y - 2y = -1 - 2y

simplify

x = -2y - 1

now that we have made x the subject in one of the equations we can plug in (or substitute) the value of x into the other equation

2x – 3y = 5

x = -2y - 1

2(-2y - 1) - 3y = 5

We can then solve for y

2(-2y - 1) - 3y = 5

Distribute the 2

-4y - 2 - 3y = 5

combine like terms -4y + -3y

-7y - 2 = 5

add 2 to both sides

-7y = 7

divide both sides by -7

y = -1

Now that we have found the value of y we can plug in the value of y into one of the equations and solve for x

x + 2y = -1

y = - 1

x + 2(-1) = -1

multiply 2 and -1

x + -2 = -1

add 2 to both sides

x = 1

So we have found that x = 1 and y = -1 therefore the solution to the system of equations is (1,-1)

7 0
2 years ago
Read 2 more answers
Part of the proceeds from a garage sale was $455 worth of $5 bills and $20 bills. If there were 6 more $5 bills than 20$ bills f
Feliz [49]

Answer:

\large \boxed{\text{17 \$20 bills and 23 \$5 bills}}

Step-by-step explanation:

               Let x = the number of $20 bills.

     Then x + 6 = the number of $5 bills  and

20x + 5(x +  6) = 455

\begin{array}{rcl}20x + 5(x + 6) & = & 455\\20x + 5x + 30 & = & 455\\25x + 30 & = & 455\\25x & = & 425\\x & = &\dfrac{425}{25}\\\\x & = &\mathbf{17}\\\end{array}

                    x = 17 = number of $20 bills

x + 6 = 17 + 6 = 23 = number of $5 bills

\text{There were }\large \boxed{\textbf{17 \$20 bills and 23 \$5 bills}}

Check:

\begin{array}{rcl}20\times17+ 5(17 + 6) & = & 455\\340 + 5\times23& = & 455\\340 + 115 & = & 455\\455 & = & 455\\\end{array}

OK.

7 0
2 years ago
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