Answer:
The equation of the tangent line passing through the point (-2,3) is
4 x + y +5 =0
Step-by-step explanation:
<u><em>Step(i):-</em></u>
<em>Given that the slope of the tangent</em>
<em> </em><em></em>
<em> m = -2( 3-1) = -4</em>
<em>Given point x = -2</em>
<em> y = f(-2) =3</em>
<em>∴The given point ( x₁ , y₁) = ( -2 ,3)</em>
<u><em>Step(ii):-</em></u>
The equation of the tangent line passing through the point (-2,3)
y -3 = -4( x+2)
y-3 = -4x -8
4x + y -3+8=0
4x +y +5=0
<u><em>Step(iii):-</em></u>
<em>The equation of the tangent line passing through the point (-2,3) is</em>
<em> 4 x + y +5 =0</em>
<em></em>
A: {<u>1</u>, 2, 3, <u>4</u>, 5, 6, <u>7</u>, 8, 9, 10, <u>11</u>, 12}
<span>B: {-2, -1, <u>1</u>, <u>4</u>, <u>7</u>, <u>11</u>}
</span>A<span> ∩ </span>B = {1, 4, 7, 11}
So the answer is B.
Intersection of two or more sets cointains only common elements.
Try a few:
1+3+5=9 too small
5+7+9= 21 just right
The greatest integer is 9
Answer:
<em>" Expected Payoff " ⇒ $ 0.830</em>
Step-by-step explanation:
Consider the probability of entering 1 ticket out of the 1000 entered;
<em>Solution ; " Expected Payoff " ⇒ $ 0.830 ( might or might not include 0 at end )</em>
Answer:
The actual SAT-M score marking the 98th percentile is 735.105.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Find the actual SAT-M score marking the 98th percentile?
This is the value of X when Z has a pvalue of 0.98. So it is X when Z = 2.055.
The actual SAT-M score marking the 98th percentile is 735.105.