The given equation is,
Thus, option (C) is the correct solution.
Answer:
7
Step-by-step explanation:
We want to find the number 4-digit of positive integers n such that removing the thousands digit divides the number by 9.
__
Let the thousands digit be 'd'. Then we want to find the integer solutions to ...
n -1000d = n/9
n -n/9 = 1000d . . . . . . add 1000d -n/9
8n = 9000d . . . . . . . . multiply by 9
n = 1125d . . . . . . . . . divide by 8
The values of d that will give a suitable 4-digit value of n are 1 through 7.
When d=8, n is 9000. Removing the 9 gives 0, not 1000.
When d=9, n is 10125, not a 4-digit number.
There are 7 4-digit numbers such that removing the thousands digit gives 1/9 of the number.
hopefully this answer can help you to answer the next question
Answer:
Yee yee delete this i just wanted points
Step-by-step explanation:
<span>D. r + (-r) = 0
</span>
The additive inverse<span> of a number a is the number that, when added to a, yields zero. This number is also known as the opposite.</span>
