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2 years ago

Help me please

Mathematics

1 answer:

Fittoniya [83]2 years ago

8 0

110a3b3c4 is yours answer.

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How to figure out proportions

juin [17]

i thibfergghgearsssgggga. dddyssxxv d xxx can find different

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3 years ago

ANSWER ASAP FOR BRAINLIEST AWARD

Mashcka [7]

we can see that

semicircle is cut off from a rectangle

Area of rectangle:

length =8

width =14

area =length*width

$Area=14*8$

$Area=112$

Area of semicircle:

diameter=8

so, radius =4

$Area=\frac{1}{2} \pi r^2$

$Area=\frac{1}{2} \pi (4)^2$

$Area=25.13274$

now, we can find resultant area

$=112-25.13274$

$=86.86726$

so, option-C..........Answer

5 0

4 years ago

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PLEASE HELP FIND THE MEDIAN OF THESE NUMBERS:<br><br> 55, 42, 78, 99, 69, 83, 74, 83, 97

Reika [66]

Median:78
mode:83
mean:75.6
q1:62
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3 years ago

What is the slope of the line?

Vsevolod [243]

Answer:

Step-by-step explanation:

Slope (m) is equal to the change in the y-coordinate divided by the change in the x-coordinate.

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5 0

3 years ago

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The sum of the ages of the father and his son is 42 years. The product of their ages is 185. Find the age of the father and the

Iteru [2.4K]

Let f and s be the ages of the father and the son. We have

$\begin{cases}f+s=42\\fs=185\end{cases}$

From the first equation we derive

$f=42-s$

Substitute this expression for f in the second equation and we have

$(42-s)s=185 \iff -s^2+42s-185=0 \iff s^2-42s+185=0$

The solutions to this equation are s=5 or s=37

Since the sum of the ages must be 42, the solutions would imply

$s=5 \implies f=37,\quad s=37\implies f=5$

We can only accept the first solution, since the second would imply a son older than his father!

4 0

3 years ago