<h3>
Answer: A. 9</h3>
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Explanation:
Draw in the segments AO and OC.
Triangle ABO is congruent to triangle CBO. We can prove this through the use of the HL theorem. HL stands for hypotenuse leg.
Since the triangles are congruent, this means the corresponding pieces AB and BC are the same length.
Then we can say:
AB+BC = AC .... segment addition postulate
AB+AB = AC .... plug in BC = AB
2*AB = AC
2*AB = 18
AB = 18/2 .... divide both sides by 2
AB = 9
In short, the chord AC is bisected by the perpendicular radius drawn in the diagram. So all we do is cut AC = 18 in half to get AB = 9.
We're told (5,-2) is on the line, that's x=5, y=-2
First one y-5 = -7, (x+2)/3=7/3, not equal
Second one y+5=3, (x-2)/3=1, not equal
Third one y+2=0, (x-5)/3=0, TRUE, equal
Fourth one, y-2=-4 (5+5)/3=10/3, not equal
Answer: third choice y+2 = (1/3)(x+5)
Answer:

Step-by-step explanation:
To solve this problem, first you have to isolate it on one side of the equation.
First, subtract 1/4 from both sides.
1/4+x-1/4<5/6-1/4
Solve.
5/6-1/4=7/12
Therefore, the correct answer is A. x< 7/12.
Answer:SAS
Explanation:In triangle ABC:
a would be the side opposite to angle A
c would be the side opposite to angle C
Combining the given, we would fine that we have the measures of two of the sides and the measure of the angle included between them.
This means that we have SAS information.
Check the attached image for visual illustration.
Hope this helps :)
Area of a square is a^2 where a is side length
if u triple the side then it is 3a
A=(3a)^2=9a^2