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3 years ago

15

i've been studying this secret message for hours but I cant seem to break the code. what it really needs is ______. A. a pretty

penny B. an ace in the hole C. a month of sundays D. a fresh pair of eyes

1 answer:

marshall27 [118]3 years ago

4 0

The correct answer to this complex equation of cheese is D

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(-9)-(-13)+(3)<img src="https://tex.z-dn.net/?f=" id="TexFormula1" title="" alt="" align="absmiddle" class="latex-formula">

Cloud [144]

Hi,

$( - 9) - ( - 13) + (3) \\ - 9 - ( - 13) + (3) \\ - 9 + 13 + 3 = 7$

Hope this helps.
r3t40

4 0

3 years ago

In the image, the distance from the swings to the slide is 35

Nikitich [7]

The Pythagorean theorem is a^2+b^2=c^2 where a and b are legs and c is the hypotenuse(longest side). you haven’t put a picture so I don’t know where 35 is a leg or the hypotenuse, but all you have to do is square the 2 shorter sides and add them and set it equal to the square of the longer side. You can do it!

5 0

3 years ago

NEED HELP! HOPE THIS IS A BETTER PHOTO

avanturin [10]

You need a picture of the data table...

4 0

3 years ago

Which unit represents speed?<br><br> joules<br> newtons<br> miles per hour<br> kilometers per second

Usimov [2.4K]

Answer:

Miles per hour and

Kilometres per second.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Will Mark Brainlest helpppp

Anvisha [2.4K]

Answer:

R = $\left[\begin{array}{ccc}-3&-2\\1&-3\\\end{array}\right]$

Step-by-step explanation:

P - Q + R = I ( I is the identity matrix )

$\left[\begin{array}{ccc}2&4\\3&5\\\end{array}\right]$ - $\left[\begin{array}{ccc}-2&2\\4&1\\\end{array}\right]$ + R = $\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right]$ ( subtract corresponding elements )

$\left[\begin{array}{ccc}2-(-2)&4-2\\3-4&5-1\\\end{array}\right]$ + R = $\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right]$

$\left[\begin{array}{ccc}4&2\\-1&4\\\end{array}\right]$ + R = $\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right]$

R = $\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right]$ - $\left[\begin{array}{ccc}4&2\\-1&4\\\end{array}\right]$ = $\left[\begin{array}{ccc}-3&-2\\1&-3\\\end{array}\right]$

6 0

3 years ago