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swat32
3 years ago
9

Beth is taking the train to see her boyfriend on Valentine's Day! The train is hundred m long and it takes 30 seconds to cross a

400 m bridge. What speed is the train going at?
Mathematics
1 answer:
marusya05 [52]3 years ago
6 0

Answer:

16.67 m/s.

Step-by-step explanation:

We have been given that a train is 100 m long and it takes 30 seconds to cross a 400 m bridge.

We will use speed formula to solve our given problem.

\text{Speed}=\frac{\text{Distance}}{\text{Time}}

We know that train has to cover the length of bridge and its own length to fully cross the bridge.

\text{Total distance covered by train}=\text{ Length of bridge+ Length of train}

\text{Total distance covered by train}=400\text{ m}+ 100\text{ m}

\text{Total distance covered by train}=500\text{ m}

Time taken by train to cross the bridge = 30 seconds.

Upon substituting these values in speed formula we will get,

\text{Speed}=\frac{500\text{ m}}{30\text{ seconds}}

\text{Speed}=16.67\frac{\text{ m}}{\text{ second}}

Therefore, the trains is going at a speed of 16.67 meters per second.

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I hope this helps you




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3 years ago
Graph the solution set to this inequality.<br> -2(x + 6) &gt; -41
vaieri [72.5K]
Do not expand the brackets, divide both sides by -2 and reverse the inequality!
So x + 6 < -41/-2 = 20.5
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3 years ago
A professional basketball team made 37.9% of its three-point field goals in one season. If 80 three-point field goal attempts ar
kompoz [17]

Answer:

The probability that more than 35 were made is 0.14686.

Step-by-step explanation:

We are given that a professional basketball team made 37.9% of its three-point field goals in one season.

80 three-point field goal attempts are randomly selected from the season.

Let \hat p = <em>sample proportion of three-point field goals made in one season.</em>

The z-score probability distribution for the sample proportion is given by;

                           Z  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}} }  ~ N(0,1)

where, p = population proprotion of three-point field goals = 37.9% = 0.379

            n = sample of three-point field goal attempts = 80

            \hat p = sample proportion of three-point field goals = \frac{35}{80} = 0.4375

Now, if 80 three-point field goal attempts are randomly selected from the season, the probability that more than 35 were made is given by = P(\hat p > 0.4375)

P(\hat p > 0.4375) = P( \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}} } > \frac{0.4375-0.379}{\sqrt{\frac{0.4375(1-0.4375)}{80}} } ) = P(Z > 1.05) = 1 - P(Z \leq 1.05)

                                                                       = 1 - 0.85314 = <u>0.14686</u>

The above probability is calculated by looking at the value of x = 1.05 in the z table which has an area of 0.85314.

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Answer:

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