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3 years ago

a golf ball is hit down a fairway. the golfer relates the time passed to the height of the ball. is this a function?

Mathematics

1 answer:

andre [41]3 years ago

7 0

Yes, considering that the ball cannot have two different heights at the same exact time.

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A biologist sets up cameras to record all the animals that come to a watering hole over a 30 day period. This is an example of w

labwork [276]

This is an example of observational study, because the biologist is not interfering or interacting with the subjects of study but just watching and registering data (recording with cameras).

The biologist is not conducting an experiment because (he is not setting up special conditions to register different responses to drive conclusions), and the biologist is not making any survey (questionnaires for example).

Answer: observational study

3 0

3 years ago

A study of 10 different weight loss programs involved 500 subjects. Each of the 10 programs had 50 subjects in it. The subjects

Yakvenalex [24]

Answer:

a) (iii) ANOVA

b) The ANOVA test is more powerful than the t test when we want to compare group of means.

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

If we assume that we have $p=10$ groups and on each group from $j=1,\dots,p=10$ we have $n_j$ individuals on each group we can define the following formulas of variation:

$SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2$

$SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2$

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2$

And we have this property

$SST=SS_{between}+SS_{within}$

Solution to the problem

Part a

(i) confidence interval

False since the confidence interval work just when we have just on parameter of interest, but for this case we have more than 1.

(ii) t-test

Can be a possibility but is not the best method since every time that we conduct a t-test we have a chance that we commit a Type I error.

(iii) ANOVA

This one is the best method when we want to compare more than 1 group of means.

(iv) Chi square

False for this case we don't want to analyze independence or goodness of fit, so this one is not the correct test.

Part b

The ANOVA test is more powerful than the t test when we want to compare group of means.

8 0

4 years ago

92/30 in simplest form

PtichkaEL [24]

Your answer is 1/15 hope this helps

6 0

3 years ago

Read 2 more answers

50^2 what is this equation for the problem

leonid [27]

50^2 means 50 squared. or 50 to the square root of 2

4 0

3 years ago

n a group of 40 people, 10 people are healthy. The 30 unhealthy people have either high blood pressure, high cholesterol, or bot

aalyn [17]

Answer:

If a person is randomly selected from this group, the probability that they have both high blood pressure and high cholesterol is P=0.25.

Step-by-step explanation:

We can calculate the number of people from the sample that has both high blood pressure (HBP) and high cholesterol (HC) using this identity:

$N(\text{HBP or HC})=N(\text{HBP})+N(\text{HC})-N(\text{HBP and HC})\\\\\\ N(\text{HBP and HC})=N(\text{HBP})+N(\text{HC})-N(\text{HBP or HC})\\\\\\ N(\text{HBP and HC})=15+25-30=10$

We can calculate the probability that a random person has both high blood pressure and high cholesterol as:

$P(\text{HBP and HC})=\dfrac{10}{40}=0.25$

3 0

3 years ago