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hram777 [196]
3 years ago
15

A bag of potting soil sells for $2, and a bag of fertilizer sells for 13. Write an expression for the Total cost of 4 bags of so

il and 2 bags of fertilizer.
A.) 13+2+4
B.) (4x2)+(2x13)
C.) 4x13
D.) 4x(2+13)
Mathematics
1 answer:
eduard3 years ago
8 0

Answer:

the answer would be B.) (4X2)+(2X13)

Step-by-step explanation:

The reason this is correct because its $2 for one bag of potting soil and since we need 4 we multiply 4 by 2 giving us 8 and since we need 2 bags of ertillizer seed and they sell for $13 we multiply 13 by 2 giving us 26. and in the end the equation is ($8)+($26) which equals $34 all together

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100 divided by 12? as a fraction<br> no wrong answers
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5 0
3 years ago
a roller coaster train with 6 passenger cars and the front decoration has a mass of 3500 kg. when the train has the front decora
Arada [10]

Answer:

The mass of each passenger is 550 kg.

The mass of front decoration is 200 Kg.

Step-by-step explanation:

Given : A roller coaster train with 6 passenger cars and the front decoration has a mass of 3500 kg. when the train has the front decoration and only 4 passenger cars, it has a mass of 2400 kg.

To find : What is the mass of the decoration and of each passenger car?

Solution :

Let the mass of each passenger is x.

Let the mass of front decoration is y.

  • When the number of passenger = 6

Mass of 6 passengers and front decoration = 3500 kg.

The equation form is 6x+y=3500 ..........[1]

  • When the number of passengers = 4

Mass of 4 passengers and front decoration = 2400 kg.

The equation form is 4x+y=2400  ........[2]

Solving equation [1] and [2]

Subtract equation [2] from [1],

6x+y-4x-y=3500-2400

2x=1100

x=550

Put value in [1],

6(550)+y=3500

3300+y=3500

y=200

Therefore, The mass of each passenger is 550 kg.

The mass of front decoration is 200 Kg.

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