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aivan3 [116]
2 years ago
14

Points frreeeeeeeeeeeee :)

Mathematics
2 answers:
Zolol [24]2 years ago
8 0

Answer:

No idea but ok

Gala2k [10]2 years ago
7 0

Answer:

thx m8

Step-by-step explanation:

:)

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Please help. I need help with my math homework and I’m confused and I only have one attempt. Thanks in Advance!
Marrrta [24]

Answer:

x>-6, x<-4

Step-by-step explanation:

|x+5|>-1

x+5>−1 (Possibility 1)

x+5−5>−1−5 (Subtract 5 from both sides)

x>−6

x+5<−(−1)(Possibility 2)

x+5<1(Simplify both sides of the inequality)

x+5−5<1−5(Subtract 5 from both sides)

x<−4

x>-6 or x<-4

3 0
3 years ago
Determine the quadratic equation for which the zeros are 1/3 and 5/2
Darya [45]

Answer:

y = 3(x2 – 7) = 3x2 – 21

Step-by-step explanation:

6 0
3 years ago
1.
creativ13 [48]
Let x represent the worth of the professional basketball player's autograph a year ago. Since his autograph's worth increased by 40% now, $364 is 1.40x. 
 
                                      364 = 1.40x

Solving for x gives x = 260.

Thus, the autograph of the basketball player was worth only $260 last year. 

4 0
3 years ago
The population of Adamsville grew from 7,000 to 12,000 in 5 years. Assuming uninhibited exponential growth, what is the expected
mr Goodwill [35]
We have that if we assume standard exponential growth, the equation of the population will be:7000*e^{kt} if we start counting from the moment that the population was 7000. We are given that 7000* e^{5k}=12000, namely that P(5)=12000 and we need to find 7000e^{(5+5)k}=7000e^{10k}. Since e^(10k)=e^(5k)*e^(5k), and since we can solve for e^(5k) from P(5), we have:
e^(5k)=12000/7000 and we can calculate P(10). P(10)=7000\frac{12000^2}{7000^2}= 20571 people.
3 0
3 years ago
Need help please help
andriy [413]

-1/3

Or, -0.3333333...

8 0
3 years ago
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