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3 years ago

Solve the equation!3 tan^3θ = tan θ

1 answer:

8 0

3 tan³ t(theta) = tan t(theta)
3 tan³ t - tan t = 0
tan t ( 3 tan² t - 1 ) = 0
tan t = 0
t 1 = k π , k ∈ Z
3 tan ² t - 1 = 0
3 tan ² t = 1
tan ² t = 1/3
tan t = +/- √3/3
t 2 = π / 6 + k π
t 3 = - π / 6 + k π , k ∈ Z

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3 years ago

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tigry1 [53]

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Step-by-step explanation:

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3 years ago

What shape is created by the rotation and what is the

zlopas [31]

Answer:

Option D: A cylinder with a circumference of about 50 units

Step-by-step explanation:

The rest of the question is the attached figure.

The square shown has a perimeter of 32 units. The square is rotated about line k. What shape is created by the rotation and what is the approximate circumference of the base? Circumference of a circle: C = 2πr

===================================================

Given: the perimeter of the square = 32

perimeter of a square is four times the length of its side

So, the side length of square = 32/4 = 8 units

The square is rotated about line k.

So, it will form a cylinder with radius 8 units.

Circumference of a circle = 2 π r

Where, r is the radius of the circle.

Circumference of the base is C = 2 π * 8

∴ C = 16π = 16 * 3.14

∴ C = 50.26548 ≈ 50

The shape is created by the rotation is a cylinder with a circumference of about 50 units.

So, the answer option is D.

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