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Kryger [21]
3 years ago
11

A small cup is 2 inches high. When stacked, each cup adds 3/32 inch to the height of the stack. How many cups are in a stack tha

t is 5 3/8 inches high?
Mathematics
2 answers:
maria [59]3 years ago
8 0
There are 37 cups in the stack
Zarrin [17]3 years ago
6 0
2+3/32times =5 3/8

Hope this heples :D
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nathan smiled at 50 people one day and recorded that 36 people smiled back at him.Based on his observations how many people shou
Olegator [25]

Given :

Nathan smiled at 50 people one day and recorded that 36 people smiled back at him.

To Find :

How many people should Nathan expect to return a smile if he smiles at 650 people over a period of time.

Solution :

Ratio of people smiled by total number of people is :

R = \dfrac{36}{50}

Now, it is given that we have to use the given conditions.

Therefore, ratio will be same :

\dfrac{s}{650}=\dfrac{36}{50}\\\\s = \dfrac{36}{50}\times 650\\\\s = 468

Therefore, number of smiles Nathan expect to return is 468.

4 0
3 years ago
each pail of plaster covers 90 square feet of ceiling. What is the least number of pails of plaster you would need to buy to cov
Dominik [7]
The area of the ceiling:
 A = 14² = 196 ft²
 We need plaster to cover 196 ft².
 196 : 90 = 2.17778
 Answer:  We have to buy 3 pails of plaster.
7 0
3 years ago
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Explain in words how you would evaluate the expression 5.1 + q ÷ 3.4 for q = 28.9
statuscvo [17]
You would plug in twenty eight point nine to the q. So it would be five point one plus twenty eight point nine divided by three point four, which equals thirteen point six.
4 0
3 years ago
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PLEASE HELP WILL GIVE BRAINLIEST. DUE TODAY
SpyIntel [72]

Step-by-step explanation:

AB = AC ( Given)

angle BAD = angle DAC. (AD bisects BAC)

AD = AD. ( common side )

abd is congruent to adc. ( SAS Axiom)

4 0
3 years ago
Find an equation for a line that is normal to the graph of y=xe^x and goes through the origin
Marina CMI [18]
Y = xe^x
dy/dx(e^x x)=>use the product rule, d/dx(u v) = v*(du)/(dx)+u*(dv)/(dx), where u = e^x and v = x:
= e^x (d/dx(x))+x (d/dx(e^x))
y' = e^x x+ e^x
y'(0) = 1 => slope of the tangent
slope of the normal = -1
y - 0 = -1(x - 0)
y = -x => normal at origin
3 0
4 years ago
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