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2 years ago

8

What is the x-coordinate of point A in a triangle with vertexes in A(3,6), B(2,4) and C(-3,3) after undergoing a translation of

12 units to the left and 17 units down?

1 answer:

kakasveta [241]2 years ago

8 0

Answer:

Step-by-step explanation:

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If 94 people attend a concert and tickets for adults cost $2.5 while tickets for children cost $1.75 and total receipts for the

Tasya [4]

Answer:

52 adults and 42 children attended the concert

Step-by-step explanation:

Given:

Total attendees=94 people

Adults tickets=$2.5

Children tickets=$1.75

Total receipts=$203.5

Let adults=a

Children=c

a+c=94 (1)

2.5a + 1.75c=203.5 (2)

From (1)

a+c=94

a=94-c

Substitute a=94-c into (2)

2.5a + 1.75c=203.5

2.5(94-c) + 1.75c=203.5

235-2.5c+1.75c=203.5

-0.75c=203.5-235

-0.75c=-31.5

Divide both sides by -0.75

-0.75c/-0.75=-31.5/-0.75

c=42

Substitute c=42 into (1)

a+c=94

a+42=94

a=94-42

=52

a=52

Therefore,

52 adults and 42 children attended the concert

3 0

2 years ago

I need help plsssssssss

Allushta [10]

I think the answer is maybe A?

8 0

3 years ago

What is Given f(x)=-5x+1. what is f(-3)<br><br> A. 19<br><br> B. 9<br><br> C. 16<br><br> D. -14

san4es73 [151]

The answer is going to be C

5 0

3 years ago

Read 2 more answers

Find ten rational number between –3and–2

creativ13 [48]

Answer:0

Step-by-step explanation:

Find the middle of the 2 numbers

6 0

2 years ago

Find the sample size, n, needed to estimate the percentage of adults who have consulted fortune tellers. Use a 0.02 margin of er

Brrunno [24]

Answer: 2172

Step-by-step explanation:

Formula to find the sample size n , if the prior estimate of the population proportion(p) is known:

$n= p(1-p)(\dfrac{z^*}{E})^2$ , where E= margin of error and z* = Critical z-value.

Let p be the population proportion of adults have consulted fortune tellers.

As per given , we have

p= 0.20

E= 0.02

From z-table , the z-value corresponding to 98% confidence interval = z*=2.33

Then, the required sample size will be :

$n= 0.20(1-0.20)(\dfrac{2.33}{0.02})^2$

$n= 0.20(0.80)(116.5)^2$

$n= 2171.56\approx2172$

Hence, the required sample size = 2172

3 0

2 years ago