Answer:
Janine is 28. Ingrid is 30.
Step-by-step explanation:
Let the ages be x and x + 2 for Janine and her sister, respectively.
x/7 + (x + 2)/3 = 14
Multiply both sides by the LCD, 21, to get rid of denominators.
21 * x/7 + 21 * (x + 2)/2 = 21 * 14
3x + 7(x + 2) = 294
3x + 7x + 14 = 294
10x = 280
x = 28
x + 2 = 30
Answer: Janine is 28. Ingrid is 30.
Answer: P(x ≥ 1) = 0.893
Step-by-step explanation:
We would assume a binomial distribution for the outcome of the investment. The formula is expressed as
P(x = r) = nCr × p^r × q^(n - r)
Where
x represent the number of successes.
p represents the probability of success.
q = (1 - r) represents the probability of failure.
n represents the number of trials or sample.
From the information given,
p = 36% = 36/100 = 0.36
q = 1 - p = 1 - 0.36
q = 0.64
n = 5
Therefore,
P(x ≥ 1) = 1 - P(x = 0)
P(x = 0) = 5C0 × 0.36^0 × 0.64^(5 - 0)
P(x = 0) = 1 × 1 × 0.107
P(x = 0) = 0.107
P(x ≥ 1) = 1 - 0.107 = 0.893
The 30,60,90 - the hypotenuse is equal to twice the length of the shorter leg , the hypotenuse side =2x , the shortest side =x and the straight side is x square root 3
Depending on how flexibly you interpret "about 20 times larger" to mean, the answers are B and D.
Check the ratios of the larger number to the smaller number:
A: (2.01 x 10^7)/(4.25 x 10^6) = 2.01/4.25 x 10^1 = 20.1/4.25 = 4.729
B: (8.21 x 10^-3)/(4.13 x 10^-4) = 8.21/4.13 x 10^1 = 82.1/4.13 = 19.879
C: (4.91 x 10^6)/(5.09 x 10^3) = 4.91/5.09 x 10^3 = 4910/5.09 = 964.637
D: (5.97 x 10^4)/(3.12 x 10^3) = 5.97/3.12 x 10^1 = 59.7/3.12 = 19.135
9514 1404 393
Answer:
(i) x° = 70°, y° = 20°
(ii) ∠BAC ≈ 50.2°
(iii) 120
(iv) 300
Step-by-step explanation:
(i) Angle x° is congruent with the one marked 70°, as they are "alternate interior angles" with respect to the parallel north-south lines and transversal AB.
x = 70
The angle marked y° is the supplement to the one marked 160°.
y = 20
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(ii) The triangle interior angle at B is x° +y° = 70° +20° = 90°, so triangle ABC is a right triangle. With respect to angle BAC, side BA is adjacent, and side BC is opposite. Then ...
tan(∠BAC) = BC/BA = 120/100 = 1.2
∠BAC = arctan(1.2) ≈ 50.2°
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(iii) The bearing of C from A is the sum of the bearing of B from A and angle BAC.
bearing of C = 70° +50.2° = 120.2°
The three-digit bearing of C from A is 120.
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(iv) The bearing of A from C is 180 added to the bearing of C from A:
120 +180 = 300
The three-digit bearing of A from C is 300.
