Solution:
1. Consider two trees which are 5 m apart. Suppose one tree is located at a distance of 45 m from my house and another tree is located 50 m from my house. Represent , distance of two trees from my house in terms of Quadratic function.
Solution:
Let location of my house when map of planet earth is drawn or on globe=x
⇒(x-45)(x-50)=0
⇒ x² - 45 x - 50 x +45 × 50 =0
⇒ x² - 95 x + 2250=0
2. Suppose age of me and my brother is 6 and 10 years. The Product of difference between age of me and my mother who is x years old and my brother and mother is 780.Find my mother's age.
Solution: Age of my mother = x years
→(x-6) × (x-10)= 780,
if you will solve it , the value of x= 36 years
Answer:
Divisor:D
Divedend: A
Quotient:C
Step-by-step explanation:
I think it would be 29 students in the larger class
Answer:
d
Step-by-step explanation:
For this case what you should do is evaluate values of x in the function and verify that they meet the result of f (x) shown in the graph.
The answer is
f (x) = - 2lxl +1
notice that
f (1) = - 2l1l + 1 = -1
f (-1) = - 2l-1l + 1 = -1
Both comply with the value of f (x) shown in the graph
answer
f (x) = - 2lxl +1
