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agasfer [191]
3 years ago
4

Which equation represents the total ionic equation for the reaction of HNO3 and NaOH?

Chemistry
2 answers:
Sliva [168]3 years ago
7 0

<u>Answer:</u> The total ionic equation for the reaction is H^+(aq.)+OH^-(aq.)\rightarrow H_2O(l)

<u>Explanation:</u>

Net ionic equation of any reaction does not include any of the spectator ions.

These are defined as the ions which do not get involved in a chemical equation. They are also defined as the ions which are found on both the sides of chemical reaction when it is present in ionic form.

The chemical equation for the reaction of nitric acid and sodium hydroxide follows:

HNO_3(aq.)+NaOH(aq.)\rightarrow NaNO_3(aq.)+H_2O(l)

Ionic form of the above equation follows:

H^+(aq.)+NO_3^-(aq.)+Na^+(aq.)+OH^-(aq.)\rightarrow Na^+(aq.)+NO_3^-(aq.)+H_2O(l)

As, sodium and nitrate ions are present on both the sides of reaction. Thus, it will not be present in the net ionic equation.

The net ionic equation for the above reaction follows:

H^+(aq.)+OH^-(aq.)\rightarrow H_2O(l)

Lostsunrise [7]3 years ago
6 0

Answer:

H⁺ + OH⁻ → H₂O.

Explanation:

  • The molecular equation is:

<em>HNO₃ + NaOH → NaNO₃ + H₂O.</em>

<em></em>

And the ionic equation is: H⁺ + OH⁻ → H₂O.

Na⁺ and NO₃⁻ ions are in aqueous solution on both sides of the equation, so they are spectator ions. They are not part of the net ionic equation.

  • So, the net ionic equation is:

H⁺ + OH⁻ → H₂O.

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Given the solubility, calculate the solubility product constant (ksp) of each salt at 25°c: (a) pbcro4, s = 4.0 × 10−5 g/l; (b)
madreJ [45]
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according to the equation:

PbCrO4(s)  →  Pb2+(aq)   +  CrO42-(aq)

so, Ksp = [Pb2+][CrO42-]

by assuming [Pb2+] = [CrO42-] = X

and when S (the solubility) = 4 x 10^-5 g/L

we have first to convert solubility from g/L to mol/L by getting the molar mass of the salt 

solubility mol/L =  solubility g/L / molar mass of salt

                           = 4 x 10^-5g/L / 323.2 g/mol

                            = 1.24 x 10^-7 mol / L

by substitution in Ksp formula:

∴Ksp = X* X

         = (1.24 x 10^-7)^2

         = 1.54 x 10^-14

b) BaC2O4:

according to this equation:

BaC2O4(s)→  Ba 2+(aq)  +  C2O4 2- (aq)  

So Ksp = [Ba2+][C2O42-]

Assume that [Ba2+] = [C2O42-] = X

when the solubility S =  0.29 g/L = X  , so we need to convert S from g/L to
mol / L 

solubility mol / L= solubility g/L / molar mass of salt

                           = 0.29 g/L / 225.34 g/mol

                           = 0.0013 mol/L

by substitution in ksp formula:

∴Ksp = X^2 

         = (0.0013)^2 

         = 1.69 x 10^-6 

C)  MnCO3: 

according to this equation :

MnCO3(s)→ Mn2+(aq)   +  CO3 2-(aq)

so, Ksp = [Mn2+][CO32-]

assume [Mn2+] = [CO32-] = X

when the solubility s = 4.2 x 10^-6 g/L so we need to convert S from g/L to mol/L by dividing on molar mass.

the solubility mol/L = solubility g/L / molar mass g/mol

                                 =.4.2 x 10^-6 /114.9 

                                 = 3.7 x 10^-8 mol/L

by substitution on ksp formula:

∴ Ksp = X*X

           = (3.7 x 10^-8)^2

           = 1.369 x 10^-15
6 0
3 years ago
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