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Firlakuza [10]
3 years ago
13

The lithosphere and the asthenosphere are made up of solid,liquid,or gas?ASAP

Chemistry
1 answer:
REY [17]3 years ago
5 0
Gas, hope this helps
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A helium filled weather balloon has a volume of 806 L at 20.9°C and 753 mmHg. it is released and rises to an altitude of 6.8 km,
OLEGan [10]
<h3>Answer:</h3>

1257.45 L

<h3>Explanation:</h3>

We are given;

  • Initial volume of Helium gas, V1 as 806 L
  • Initial temperature of Helium gas,T1 as 20.9°C
  • Initial pressure of Helium gas, P1 as 753 mmHg
  • Pressure of Helium at the altitude 6.8 km, P2 as 417 mmHg
  • Temperature of Helium gas at the altitude 6.8 Km, T2 as -19.1°C

But, K = °C + 273.15

Therefore, T1 = 294.05 K and T2 = 254.05 K

  • We are required to calculate the new volume of the balloon at 6.8 km.
  • To determine the new volume we are going to use the combined gas law.
  • According to the combined gas law, \frac{P1V1}{T1}=\frac{P2V2}{T2}

Thus, rearranging the formula;

V2=\frac{P1V1T2}{P2T1}

V2=\frac{(753)(806L)(254.05K)}{(417)(294.05)}

V2=1257.45L

Therefore, the volume of the balloon at an altitude of 6.8 km is 1257.45 L

7 0
3 years ago
Calculate the molar concentrations of H+ and OH− in solutions that have the following pH values:
Anastaziya [24]

Answer:

Explanation:

a )

pH = - log[ H⁺]

8.26 = - log[ H⁺]

[ H⁺] = 10⁻⁸°²⁶ mole / l

= 5.49 x 10⁻⁹ moles / l

[ H⁺] [OH⁻] = 10⁻¹⁴

[OH⁻] = 10⁻¹⁴ / 5.49 x 10⁻⁹

= .182  x 10⁻⁵ moles / l

b )

10.25 = - log[ H⁺]

[ H⁺] = 10⁻¹⁰°²⁵ mole / l

= 5.62 x 10⁻¹¹ moles / l

[ H⁺] [OH⁻] = 10⁻¹⁴

[OH⁻] = 10⁻¹⁴ / 5.62 x 10⁻¹¹

= .178 x 10⁻³ moles / l

c )

4.65 = - log[ H⁺]

[ H⁺] = 10⁻⁴°⁶⁵ mole / l

= 2.24 x 10⁻⁵ moles / l

[ H⁺] [OH⁻] = 10⁻¹⁴

[OH⁻] = 10⁻¹⁴ / 2.24 x 10⁻⁵

= .4464 x 10⁻⁹ moles / l

7 0
3 years ago
Which particles are found in an atom have charges
-BARSIC- [3]
Atomic particles Because the usually have a chain reaction when blown up
5 0
3 years ago
Read 2 more answers
A compound has a molecular weight of 146 g/mol. A 0.3250 g sample of the compound contains 0.1605 g of carbon, 0.0220 g of hydro
Sonbull [250]

Answer: The molecular formula is C_6H_{10}S_2

Explanation:

We are given:

Mass of C = 0.1605 g

Mass of H= 0.0220 g

mass of S = 0.1425 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{0.1605g}{12g/mole}=0.0134moles

Moles of H =\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.0220g}{1g/mole}=0.0220moles

Moles of S =\frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{0.1425g}{32g/mole}=0.0044moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = \frac{0.0134}{0.0044}=3

For H = \frac{0.0220}{0.0044}=5

For S =\frac{0.0044}{0.0044}=1

The ratio of C : H: S=  3: 5: 1

Hence the empirical formula is C_3H_5S

The empirical weight of C_3H_5S = 3(12)+5(1)+1(32)= 73g.

The molecular weight = 146 g/mole

Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{146}{73}=2

The molecular formula will be=2\times C_3H_5S=C_6H_{10}S_2

7 0
3 years ago
1. If 20 moles of HCl was placed in 40 liters of an
anastassius [24]

Answer:

A) 0.50 M

Explanation:

The computation of the number of molarity of the NaOH is given below:

As we know that

Molarity = Moles ÷ liters

where

Moles is 20

And, the liters is 40

So, the molarity is

= 20 ÷ 40

= 0.50 M

hence, the molarity of the NaOH  solution is 0.50 M

Therefore the A option is correct

8 0
3 years ago
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