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scZoUnD [109]
1 year ago
10

Atoms with the same number of protons but different masses (from different numbers of neutrons) are called:

Chemistry
1 answer:
____ [38]1 year ago
5 0

Atoms with the same number of protons but different masses are called Isotopes.

<h3>What are Isotopes?</h3>

An isotope is one of two or more chemical elements that exist in different forms. Varied isotopes of an element have the same atomic number and protons in their nuclei, giving them the same atomic weight. However, each elemental isotope has a different amount of neutrons, which changes its atomic weight.

isobars - Isobars are atoms (nuclides) of several chemical elements that have diverse chemical characteristics but share the same physical characteristics. So, we may define isobars as elements with the same mass number but a different atomic number.

to learn more about isotopes go to -

https://brainly.in/question/1341808

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I have for Decompostion

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Identify the correct coefificients to balance it<br> -C3H8+O2 to -CO2 +-H2O
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Answer:

{\rm 1\; C_3H_8} + {\rm 5\; O_2} \to {3\; \rm CO_2} + {4\; \rm H_2O}.

Explanation:

{\rm ?\; C_3H_8} + {\rm ?\; O_2} \to {?\; \rm CO_2} + {?\; \rm H_2O}.

Among the four species in this reaction, \rm C_3H_8 is species with the largest number of atoms per molecule. Assume that the coefficient of this compound is 1.

{\rm 1\; C_3H_8} + {\rm ?\; O_2} \to {?\; \rm CO_2} + {?\; \rm H_2O}.

Number of atoms on the left-hand side of the reaction:

  • \rm C: 1 \times 3 = 3.
  • \rm H: 1 \times 8 = 8.
  • \rm O: not found yet.

By the conservation of atoms, the number of atoms on the right-hand side of the reaction should match those on the left-hand side. In this reaction, \rm CO_2 is the only product with carbon atoms, whereas \rm H_2O is the only product with hydrogen atoms. These 3 carbon atoms and 8 hydrogen atoms would correspond to:

  • 3 / 1 = 3 \rm CO_2 molecules, and
  • 8 / 2 = 4 \rm H_2O molecules.

{\rm 1\; C_3H_8} + {\rm ?\; O_2} \to {3\; \rm CO_2} + {4\; \rm H_2O}.

Number of atoms on the right-hand side of the reaction:

  • \rm C: 3 \times 1 = 3.
  • \rm H: 4 \times 2 = 8.
  • \rm O: 3 \times 2 + 4 \times 1 = 10.

The number of \rm O atoms on the left-hand side should match those on the right-hand side. In this reaction, \rm O_2 is the only reactant with \rm O\! atoms. These 10 \rm \! O atoms would correspond to:

  • 5 \rm O_2 molecules.

{\rm 1\; C_3H_8} + {\rm 5\; O_2} \to {3\; \rm CO_2} + {4\; \rm H_2O}.

5 0
2 years ago
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