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mel-nik [20]
3 years ago
12

To save time, you can approximate the initial mass of the solid to the nearest ±1 g. For example, if you are asked to add 14.3 g

of copper, add between 13 g and 15 g. Which of the following sets include two samples with an equal density? Which all that apply below 15.4 g gold and 18.7 g silver 15.2 g copper and 50.0 g copper 20.2 g silver and 20.2 g copper 11.2 g gold and 14.9 g gold
Chemistry
2 answers:
borishaifa [10]3 years ago
8 0

<u>Answer:</u> The correct answer is 15.2 g copper and 50.0 g copper and 11.2 g gold and 14.9 g gold.

<u>Explanation:</u>

Density of an object is defined as the ratio of its mass and volume. The chemical equation representing density of an object is:  

\text{Density of object}=\frac{\text{Mass of object}}{\text{Volume of object}}

Density is considered as an intensive property. Intensive property is the property that does not depend on the amount of substance. It remains same.

The density of a particular substance remains the same.

<u>For Example:</u> Density of nickel will remain the same for 100 grams or 0.01 grams of nickel sample which is 8.908 g/mL

Hence, the correct answer is 15.2 g copper and 50.0 g copper and 11.2 g gold and 14.9 g gold.

tensa zangetsu [6.8K]3 years ago
6 0

Answer: Set with equal densities are:

15.2 g copper and 50.0 g copper ; 11.2 g gold and 14.9 g gold

Explanation:

Density is defined as mass of the substance present in unit volume of the substance.

Density=\frac{Mass}{Volume}

It is an intensive property which means that two different masses of same substance will have same value of density under same conditions.

So, from the given samples with equal density are:

  • 15.2 g copper and 50.0 g copper will have the same value density.
  • 11.2 g gold and 14.9 g gold will have the same value density.
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Silicon atoms have 14 protons.

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Silicon atoms have 14 electrons.

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Water is a great solvent. For example, it causes ionic compounds like sodium chloride (table salt) to dissociate. One of these r
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the electrolysis reaction is a non- spontaneous reaction

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Mario uses a hot plate to heat a beaker of 50mL of water. He used a thermometer to measure the temperature of the water. The wat
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The boiling point decreases as the volume decreases.

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Titration of 0.824 g of potassium hydrogen phthalate required 38.314 g of naoh solution to reach the end point detected by pheno
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1.062 mol/kg.

<em>Step 1</em>. Write the balanced equation for the neutralization.

MM = 204.22 40.00

KHC8H4O4 + NaOH → KNaC8H4O4 + H2O

<em>Step 2</em>. Calculate the moles of potassium hydrogen phthalate (KHP)

Moles of KHP = 824 mg KHP × (1 mmol KHP/204.22 mg KHP)

= 4.035 mmol KHP

<em>Step 3</em>. Calculate the moles of NaOH

Moles of NaOH = 4.035 mmol KHP × (1 mmol NaOH/(1 mmol KHP)

= 4.035 mmol NaOH

<em>Step 4</em>. Calculate the mass of the NaOH

Mass of NaOH = 4.035 mmol NaOH × (40.00 mg NaOH/1 mmol NaOH)

= 161 mg NaOH

<em>Step 5</em>. Calculate the mass of the water

Mass of water = mass of solution – mass of NaOH = 38.134 g - 0.161 g

= 37.973 g

<em>Step 6</em>. Calculate the molal concentration of the NaOH

<em>b</em> = moles of NaOH/kg of water = 0.040 35 mol/0.037 973 kg = 1.062 mol/kg

3 0
4 years ago
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