What is the value for the expression -5+ 5

$2000 at 9% for 6months what is the balance of the account

Vlad1618 [11]

Answer:

$2090

Step-by-step explanation:

Amt = Principal x rate x time (in years)

A = 2000 x .09 x .5

7 0

3 years ago

A survey of 270 young professionals found that one dash eighth of them use their cell phones primarily for e-mail. Can you conc

IceJOKER [234]

Answer:

As 0.17 is below the upper limit of the confidence interval, so we can conclude that the population proportion is less than 0.17.

Step-by-step explanation:

We are given that a survey of 270 young professionals found that one dash eighth of them use their cell phones primarily for e-mail.

Firstly, the Pivotal quantity for 95% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of people who use their cell phones primarily for e-mail = $\frac{1}{8}$ = 0.125

n = sample of young professionals = 270

p = population proportion

Here for constructing 95% confidence interval we have used One-sample z test for proportions.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

95% confidence interval for p = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.125-1.96 \times {\sqrt{\frac{0.125(1-0.125)}{270} } }$ , $0.125+1.96 \times {\sqrt{\frac{0.125(1-0.125)}{270} } }$ ]

= [0.08 , 0.16]

Therefore, 95% confidence interval for the population proportion who use cell phones primarily for e-mail is [0.08 , 0.16].

Since, the above confidence interval have values which is less than 0.17; so we conclude that the population proportion is less than 0.17.

3 0

4 years ago

Clues:

Ann [662]

Answer:

180

Step-by-step explanation:

hehe

2 90

3 60

4 45

5 36

6 30

9 20

90 = 2

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5 0

3 years ago

Lucy graphed the relationship between the temperature and the change in the number of people sledding at a park. The xxx-coordin

Shalnov [3]

Answer: quadrant 1

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

An excavation has a volume of 203 cubic feet. The material weighs 1,200 pounds per cubic yard. What is the weight of the exca- v

Andrew [12]

Answer: Option 'd' is correct.

Step-by-step explanation:

Since we have given that

Volume of an excavation = 203 cubic feet

Weight of the material = 1200 pounds per cubic yard

So, the weight of the excavation would be

Volume of an excavation × Weight of the material

$=203\times 1200\\\\=243,600\ pounds$

Hence, the weight of the excavation is 243,600 pounds.

Therefore, Option 'd' is correct.

3 0

3 years ago