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Lera25 [3.4K]
3 years ago
9

Consider the polynimial equation x(x-3)(x-6)(x-7)=0. Which of the following are zeros of the equation? Selet all that apply

Mathematics
1 answer:
Zepler [3.9K]3 years ago
8 0

<u><em>Answer:</em></u>

<u>The zeroes of the equation are:</u>

0, 3, 6 and 7

<u><em>Explanation:</em></u>

<u>Zeroes of an equation</u> are defined as values of x which make the equation equivalent to zero

<u>Remember that</u> in multiplication, if any of the terms is zero, then the product is equal to zero

<u>The given equation is:</u>

x(x-3)(x-6)(x-7) = 0

Now, we will take each term, equate it to zero and find the corresponding x value which makes this term a zero

<u>For the first term:</u>

x = 0 .................> 1st zero

<u>For the second term:</u>

x-3 = 0 .............> x = 3 ................> 2nd zero

<u>For the third term:</u>

x-6 = 0 ............> x = 6 .................> 3rd zero

<u>For the fourth term:</u>

x-7 = 0 ............> x = 7 ...................> 4th zero

Now, from the above, we can conclude that:

The zeroes of the equation are 0, 3, 6 and 7

<u>Another solution:</u>

Zeroes of an equation are represented graphically as the intersection between the function and the x-axis

Therefore, we can graph the function and get the intersection

The graph is attached below and the intersections are shown to be at:

(0,0) , (3,0) , (6,0) and (7,0)

This means that the zeroes are 0, 3, 6 and 7

Hope this helps :)

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