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3 years ago

If 0 is in quadrant II and sin^2 0=3/4 evaluate tan0

Mathematics

1 answer:

xeze [42]3 years ago

8 0

Answer:

yes. ..........................

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A boat can travel with a speed of 13 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boa

ser-zykov [4K]

Answer:

t=4h

Steps below

Step-by-step explanation:

We know:

speed of boat with respect to earth: 13 km

speed of stream with respect to earth: 4 km

13 km/h + 4 km/h = 17 km/h The time to travel 68 km with this speed is thus t = 68 km 17 km h = 4 h

Hope this helps.

4 0

3 years ago

The municipal swimming pool in Nicetown has three different ways of paying for individual open swimming. Todd is trying to decid

balandron [24]

Sllope intercept form is y=mx+b
m is the slope , b is the y itnercept

so early pay
cost=70 flat rate
x=infinity
the equation would be y=70

deposit pluss
you have to pay an initial one time payment of 15 so
y=mx+15
then 4 dollars per day
4 times number of days
y=4x+15

daily pay is 6 dollars per day so 6 times number of days
y=6x

1.
a. y=70
b. y=4x+15
c. y=4x

6 0

3 years ago

If a and b are positive constants and if a(x-y) = b(y-x), what is the value of the ratio of x/y?

Mekhanik [1.2K]

Answer: x/y=1

Step-by-step explanation:

a(x-y)=b(y-x)

(a+b)x=(a+b)y

x/y=1 ans

hope this helps

8 0

3 years ago

A jumbo crayon is composed of a cylinder with a conical tip. The cylinder is 12 cm tall with a radius of 1.5 cm, and the cone ha

s2008m [1.1K]

Answer:

Part 1) The lateral area of the cone is $LA=2\pi\ cm^{2}$

Part 2) The lateral surface area of the cylinder is $LA=36\pi\ cm^{2}$

Part 3) The surface area of the crayon is $SA=41.50\pi\ cm^{2}$

Step-by-step explanation:

Part 1) Find the lateral area of the cone

The lateral area of the cone is equal to

$LA=\pi rl$

we have

$r=1\ cm$

$l=2\ cm$

substitute

$LA=\pi (1)(2)$

$LA=2\pi\ cm^{2}$

Part 2) Find the lateral surface area of the cylinder

The lateral area of the cylinder is equal to

$LA=2\pi rh$

we have

$r=1.5\ cm$

$h=12\ cm$

substitute

$LA=2\pi (1.5)(12)$

$LA=36\pi\ cm^{2}$

Part 3) Find the surface area of the crayon

The surface area of the crayon is equal to the lateral area of the cone, plus the lateral area of the cylinder, plus the top area of the cylinder plus the bottom base of the crayon

Find the area of the bottom base of the crayon

$A=\pi[r2^{2}-r1^{2}]$