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MariettaO [177]
3 years ago
8

consider the following set of equations: equation a: y = 2x 4 equation b: y = 3x 1 which of the following is a step that can be

used to find the solution to the set of equations? 2x 4 = 3x 1 2x = 3x 4 2x 4 = 3x 2x 1 = 3x 4
Mathematics
2 answers:
Marina CMI [18]3 years ago
5 0

Answer:

2x+4=3x+1.

Step-by-step explanation:

Consider the given set of equations

y=2x+4

y=3x+1

We need to find the step that can be used to find the solution to the set of equations.

We can find the solution of given system of equations by equating both equations.

2x+4=3x+1

Isolate variable terms.

4-1=3x-2x

3=x

Therefore, the required equation is 2x+4=3x+1.

loris [4]3 years ago
4 0
Y = 2x + 4 and y = 3x + 1
Therefore, 2x + 4 = 3x + 1
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Answer:

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Step-by-step explanation:

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7 0
3 years ago
You throw a stone with a force of 55.1 N. It accelerates at 41.6 m/s2.
Mice21 [21]

Answer:

Mass = 1.3 Kilograms.

Step-by-step explanation:

Given the following data;

Force = 55.1 N

Acceleration = 41.6 m/s²

To find the mass of the stone in kg;

Newton's Second Law of Motion states that the acceleration of a physical object is directly proportional to the net force acting on the physical object and inversely proportional to its mass.

Mathematically, it is given by the formula;

Force = mass * acceleration

Substituting into the formula, we have;

55.1 = mass * 41.6

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6 0
3 years ago
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KatRina [158]

Answer:

n = 60.22

Step-by-step explanation:

Hello

To find Sn, we need to draw out equations for each a₇ and a₁₉

In an arithmetic progression,

Sn = a + (n-1)d

Where Sn = sum of the A.P

a = first term

d = common difference

a₇ = 32

32 = a + (7-1)d

32 = a + 6d ........equation (i)

a₁₉ = 140

140 = a + (19-1)d

140 = a + 18d .........equation (ii)

Solve equation (i) and (ii) simultaneously

From equation (i)

32 = a + 6d

Make a the subject of formula

a = 32 - 6d .....equation (iii)

Put equation (iii) into equation (ii)

140 = (32 - 6d) + 18d

140 = 32 - 6d + 18d

Collect like terms

140 - 32 = 12d

12d = 108

d = 108 / 12

d = 9

Put d = 9 in equation (i)

32 = a + 6(9)

32 = a + 54

a = 32 - 54

a = -22

When Sn = 511

Sn = a + (n - 1)d

Substitute and solve for n

511 = -22 + (n-1) × 9

511 = -22 + 9n - 9

511 = -31 + 9n

511 + 31 = 9n

542 = 9n

n = 542 / 9

n = 60.22

5 0
3 years ago
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