Answer:
Jay started with $148.5 and Kay with $24.75.
Step-by-step explanation:
With the information provided you know that Jay had 6 times as much money as Kay wich can be expressed as:
J=6K, where
J is the money Jay had
K is the money Kay had
Also, you know that Jay gave Kay $33 and Jay now has twice as much money as Kay, which would be:
J-33=2(K+33)
Now, you can replace J=6K in this equation and solve for K:
6K-33=2K+66
6K-2K=66+33
4K=66
K=24.75
Then, you can replace the value of K in J=6K:
J=6*24.75
J=148.5
According to this, the answer is that Jay started with $148.5 and Kay with $24.75.
Answer:
5 years and 5 months
Step-by-step explanation:
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<u>Compound Interest Formula</u>
where:
- A = final amount
- P = principal amount
- r = interest rate (in decimal form)
- n = number of times interest applied per time period
- t = number of time periods elapsed
Given:
- A = $17,474.00
- P = $7,790.00
- r = 15% = 0.15
- n = 12
- t = number of years
Substitute the given values into the formula and solve for t:
Therefore, the money was in the account for 5 years and 5 months (to the nearest month).
Answer:
2nt one
Step-by-step explanation:
To calculate this probability we must take into account that there is the same probability that any of the 3 urns is chosen.
This probability is:
P (U1) = P (U2) = P (U3) = 1/3
Urn 1 contains 7 black and 3 red marbles
Urn 2 contains 2 black and 8 marbles network
Urn 3 contains 5 black marbles and 5 red marbles.
The probability of obtaining a black marble in Urn 1 is 7/10.
The probability of obtaining a black marble in Urn 2 is 2/10
The probability of obtaining a black marble in Urn 3 is 5/10.
Then we look for the probability of obtaining a black marble from urn 1 or a black marble from urn 2 or a black marble from urn 3. This is:
P (U1yB) + P (U2yB) + P (U3yB)
So:
(1/3) * (7/10) + (1/3) * (2/10) + (1/3) * (5/10) = 0,2333 + 0,0667 + 0,1667 = 0, 4667.
The probability that it is a black marble is 46.67%
