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3 years ago

I NEED HELP BEING TIMED

Mathematics

2 answers:

Vedmedyk [2.9K]3 years ago

5 0

Acute scalene because they are all smaller than 90 degrees but different lengths

Ne4ueva [31]3 years ago

4 0

Acute Scalene because they are less than 90 degrees and have different lengths. Hope this helps!>_< Sorry if its wrong!<3

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(3n² p⁴) Idk how to solve it

tester [92]

me neither but this is what i got

3n² p⁴

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3 years ago

In Exercises 5-7, find all the exact t-values for which the given statement is true,

bearhunter [10]

Answer: See Below

Step-by-step explanation:

NOTE: You need the Unit Circle to answer these (attached)

5) cos (t) = 1

Where on the Unit Circle does cos = 1?

Answer: at 0π (0°) and all rotations of 2π (360°)

In radians: t = 0π + 2πn

In degrees: t = 0° + 360n

******************************************************************************

$6)\quad sin (t) = \dfrac{1}{2}$

Where on the Unit Circle does $sin = \dfrac{1}{2}$

Hint: sin is only positive in Quadrants I and II

$\text{Answer: at}\ \dfrac{\pi}{6}\ (30^o)\ \text{and at}\ \dfrac{5\pi}{6}\ (150^o)\ \text{and all rotations of}\ 2\pi \ (360^o)$

$\text{In radians:}\ t = \dfrac{\pi}{6} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{6} + 2\pi n$

In degrees: t = 30° + 360n and 150° + 360n

******************************************************************************

$7)\quad tan (t) = -\sqrt3$

Where on the Unit Circle does $\dfrac{sin}{cos} = \dfrac{-\sqrt3}{1}\ or\ \dfrac{\sqrt3}{-1}\quad \rightarrow \quad (1,-\sqrt3)\ or\ (-1, \sqrt3)$

Hint: sin and cos are only opposite signs in Quadrants II and IV

$\text{Answer: at}\ \dfrac{2\pi}{3}\ (120^o)\ \text{and at}\ \dfrac{5\pi}{3}\ (300^o)\ \text{and all rotations of}\ 2\pi \ (360^o)$

$\text{In radians:}\ t = \dfrac{2\pi}{3} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{3} + 2\pi n$

In degrees: t = 120° + 360n and 300° + 360n

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3 years ago

CAN SOMEONE HELP PLZZZ PLZZ PLZZZZZ ILL GIVE EVERYTHING

Studentka2010 [4]

Answer:

what do u need help with?

Step-by-step explanation:

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3 years ago

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5. Find the surface area of a sphere with

alexandr402 [8]

It should be A) 28.26cm

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3 years ago

If angle I is congruent to angle K, find JK.

Rudiy27

Using Isosceles triangle theorem we can determine that JI = JK
Thus
5x + 4 = 2x+7
3x = 3
x=1
Plug it back into the eqution for JK
2(1) + 7 = JK
9 = JK

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3 years ago

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