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2 years ago

I NEED HELP BEING TIMED

Mathematics

2 answers:

Vedmedyk [2.9K]2 years ago

5 0

Acute scalene because they are all smaller than 90 degrees but different lengths

Ne4ueva [31]2 years ago

4 0

Acute Scalene because they are less than 90 degrees and have different lengths. Hope this helps!>_< Sorry if its wrong!<3

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THE GREATEST PRODUCT

Alex17521 [72]

Answer:

7*6543=45801

Step-by-step explanation:

We have the digits 34567 and must arrange them into a product with the largest possible value.

It's clear that we must place the largest digits to the left, so they represent larger numbers to multiply.

Let's try with:

7654*3=22962

765*43=32895

76*543=41268

7*6543=45801

This last combination definitely produces the largest product

Answer: 7*6543=45801

5 0

2 years ago

Ishaan is 3 times as old as Chris and is also 14 years older than Chris. How old is ishaan?

hram777 [196]

Answer:We are also given that Ishaan is 14 years older than Christopher, so I is also 14 more than c. This gives that I = c + 14. Since I = 3c and I = c + 14, we have that 3c is equal to c + 14, giving the equation 3c = c + 14.

well this is from google and just so u know the letters stand for the names

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3 years ago

Jenny surveyed 40 students at her school and found that 0.55 of the students she surveyed said their favorite class is math. Ano

Leno4ka [110]

C.) 30 since they both have 5's just take them out then subtract 50 and 20 *but make sure u take out the decimal though* so after u subtract u will get 30 then line it up and put the decimal back then it will be .30

7 0

2 years ago

Dwayne drove 18 miles to the airport to pick up his father and then returned home. On the return trip he was able to drive an av

Nesterboy [21]

Answer:

30 mph

Step-by-step explanation:

Let d = distance (in miles)

Let t = time (in hours)

Let v = average speed driving to the airport (in mph)

⇒ v + 15 = average speed driving from the airport (in mph)

Using: distance = speed x time

$\implies t=\dfrac{d}{v}$

Create two equations for the journey to and from the airport, given that the distance one way is 18 miles:

$\implies t=\dfrac{18}{v} \ \ \textsf{and} \ \ t=\dfrac{18}{v+15}$

We are told that the total driving time is 1 hour, so the sum of these expressions equals 1 hour:

$\implies \dfrac{18}{v} +\dfrac{18}{v+15}=1$

Now all we have to do is solve the equation for v:

$\implies \dfrac{18(v+15)}{v(v+15)} +\dfrac{18v}{v(v+15)}=1$

$\implies \dfrac{18(v+15)+18v}{v(v+15)}=1$

$\implies 18(v+15)+18v=v(v+15)$

$\implies 18v+270+18v=v^2+15v$

$\implies v^2-21v-270=0$

$\implies (v-30)(v+9)=0$

$\implies v=30, v=-9$

As v is positive, v = 30 only

So the average speed driving to the airport was 30 mph

(and the average speed driving from the airport was 45 mph)

8 0

1 year ago

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R(x)=2√x s(x)=√x (r/s)(3)

anygoal [31]

This is a trick question. First just understand that any number over itself is 1 so $\frac{2 \sqrt{x} }{\sqrt{x}}$ is just $2 * \frac{ \sqrt{x} }{ \sqrt{x}} = 2$ so it is just 2

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3 years ago

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