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Wewaii [24]
3 years ago
11

How many minutes will it take to electroplate 60.1 g of gold by running 5.00 a of current through a solution of au (aq?

Chemistry
2 answers:
Akimi4 [234]3 years ago
8 0

Answer:

It would take 0.1 minutes (approximately 6 seconds)

Explanation:

Applying the Faraday's first law of electrolysis which states that,

    m = ZIt

where m is the mass electroplated, Z is the electrochemical equivalence of the element, I is the current and t is the time taken.

Z of gold = 2.04352g/As

Thus,

t = \frac{m}{ZI}

   = \frac{60.1}{2.04352 *5}

   = 5.882 s

To determine the time in minute, divide by 60;

t = 0.0980minute

t = 0.1 minute

Elden [556K]3 years ago
3 0
For this problem, we use the Faradays law to relate the mass electroplated and the current passed through. We do as follows:

60.1 g (1 mol / 196.67 g) (1 mol e- / 1 mol Au) ( 96500 C / 1 mol e- ) = 29486.25 C

Q = It
29486.25 = 5t
t = 5897.85 s = 98.30 min

Hope this answers the question.
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How many Sodium (NA) Atoms are in Methylene?​
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Answer:

No Sodium(Na) in methylene

Explanation:

Methylene is an organic compound

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3 years ago
Need help with question please ..<br> -20 points
san4es73 [151]

Answer:

B oklolol

[tex]\purple{\rule{45pt}{7pt}}\purple{\rule{45pt}{999999pt}}[tex]

8 0
2 years ago
A student who was training for a cross-country race jogged for 1.0 hour and covered a distance of 1.5 kilometers. How much farth
densk [106]

Answer:

He would travel 3 kilometers.

Explanation:

Since he had already covered 1.5 kilometers in the time of 1 hour that means if he jogged for 1 more hour assuming he is going at the same pace he would've jogged 1.5 kilometers again and when you add that to the 1.5 kilometers he started with it would add up to 3 kilometers.

4 0
3 years ago
My theoretical yield of beryllium chloride was 10.7 grams. If my actual yield was 4.5 grams, what was my percent yield?
artcher [175]

Answer:

The percent yield of this reaction is 42.1 % (option B)

Explanation:

Step 1: Data given

Theoretical yield of beryllium chloride = 10.7 grams

actual yield of beryllium chloride = 4.5 grams

Step 2: Calculate the percent yield for this reaction

Percent yield = (actual yield / theoretical yield) * 100%

Percent yield = (4.5 grams / 10.7 grams ) * 100 %

Percent yield = 42.1 %

The percent yield of this reaction is 42.1 % (option B)

6 0
3 years ago
8. Calculate (H^+), (OH^-), pOH and the pH for a 0.00024 M solution of calcium hydroxide. Must show work!
Margaret [11]

Answer:

1. [H⁺] = 2.0×10¯¹¹ M

2. [OH¯] = 4.8×10¯⁴ M

3. pOH = 3.3

4. pH = 10.7

Explanation:

From the question given above, the following data were obtained obtained:

Molarity of Ca(OH)₂ = 0.00024 M

We'll begin by calculating the concentration of the hydroxide ion [OH¯]. This can be obtained as follow:

Ca(OH)₂ (aq) —> Ca²⁺ + 2OH¯

From the balanced equation above,

1 mole of Ca(OH)₂ produced 2 moles of OH¯.

Therefore, 0.00024 M Ca(OH)₂ will produce = 2 × 0.00024 = 4.8×10¯⁴ M OH¯

Thus, the concentration of the hydroxide ion [OH¯] is 4.8×10¯⁴ M

Next, we shall determine the pOH of the solution. This can be obtained as follow:

Concentration of the hydroxide ion [OH¯] = 4.8×10¯⁴ M

pOH =?

pOH = –Log [OH¯]

pOH = –Log 4.8×10¯⁴

pOH = 3.3

Next, we shall determine the pH of the solution. This can be obtained as follow:

pOH = 3.3

pH =?

pH + pOH = 14

pH + 3.3 = 14

Collect like terms

pH = 14 – 3.3

pH = 10.7

Finally, we shall determine the concentration of hydrogen ion [H⁺]. This can be obtained as follow:

pH = 10.7

Concentration of hydrogen ion [H⁺] =?

pH = –Log [H⁺]

10.7 = –Log [H⁺]

Divide both side by –1

–10.7 = Log [H⁺]

Take the antilog of –10.7

[H⁺] = Antilog (–10.7)

[H⁺] = 2.0×10¯¹¹ M

SUMMARY:

1. [H⁺] = 2.0×10¯¹¹ M

2. [OH¯] = 4.8×10¯⁴ M

3. pOH = 3.3

4. pH = 10.7

5 0
3 years ago
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