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Wewaii [24]
3 years ago
11

How many minutes will it take to electroplate 60.1 g of gold by running 5.00 a of current through a solution of au (aq?

Chemistry
2 answers:
Akimi4 [234]3 years ago
8 0

Answer:

It would take 0.1 minutes (approximately 6 seconds)

Explanation:

Applying the Faraday's first law of electrolysis which states that,

    m = ZIt

where m is the mass electroplated, Z is the electrochemical equivalence of the element, I is the current and t is the time taken.

Z of gold = 2.04352g/As

Thus,

t = \frac{m}{ZI}

   = \frac{60.1}{2.04352 *5}

   = 5.882 s

To determine the time in minute, divide by 60;

t = 0.0980minute

t = 0.1 minute

Elden [556K]3 years ago
3 0
For this problem, we use the Faradays law to relate the mass electroplated and the current passed through. We do as follows:

60.1 g (1 mol / 196.67 g) (1 mol e- / 1 mol Au) ( 96500 C / 1 mol e- ) = 29486.25 C

Q = It
29486.25 = 5t
t = 5897.85 s = 98.30 min

Hope this answers the question.
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3 years ago
When 1 mole of H2(g) reacts with F2(g) to form HF(g) according to the following equation, 542 kJ of energy are evolved H2(g) + F
topjm [15]

Answer: The reaction is exothermic. The value of q is  -542 kJ.

Explanation:

Endothermic reactions are defined as the reactions in which energy of the product is greater than the energy of the reactants. The total energy is absorbed in the form of heat and  for the reaction comes out to be positive.

Exothermic reactions are defined as the reactions in which energy of the product is lesser than the energy of the reactants. The total energy is released in the form of heat and  for the reaction comes out to be negative.

Thus H_2(g)+F_2(g)\rightarrow 2HF(g) evolves heat , it is exothermic in nature. The value of q is -542kJ.

7 0
3 years ago
The volume of a gas at 7.00°c is 49.0 ml. if the volume increases to 74.0 ml and the pressure is constant, what will the tempera
marshall27 [118]
Using charles law
v1/t1=v2/t2
v1=49ml
v2=74
t1=7+273=280k
t2=?
49/280=74/t2
0.175=74/t2  cross multiply
0.175t2=74
t2=74/0.175
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8 0
3 years ago
Rolls of foil are 302 mm wide and 0.018 mm thick. (The density of foil is 2.7 g/cm3 .)
Kruka [31]

Answer:

The length of foil will be 8107.81 cm or 81.7081 m.

Explanation:

Given data:

Width of roll of foil = 302 mm

Height or thickness = 0.018 mm

Density of foil = 2.7 g/cm³

Mass of foil = 1.19 Kg

Length of foil = ?

Solution:

d = m/ v

v = length (l) × width (w) × height (h)

First of we will convert the Kg into gram and mm into cm.

one Kg = 1000 g

1.19 × 1000 = 1190 g

one cm = 10 mm

302 / 10 = 30.2 cm

0.018 / 10 =  0.0018 cm

Now we will put the values in formula:

d = m/ l× h× w

l = m / d × h× w

l = 1190 g / 2.7 g/cm³× 30.2 cm × 0.0018 cm

l = 1190 g/ 0.146772 g/cm

l = 8107.81 cm or 81.7081 m

3 0
3 years ago
Which of the following is true if the net force on an object is zero? (1 pt) a. The object must be at rest. b. The object’s spee
prohojiy [21]

Explanation:

the object must be at rest

5 0
3 years ago
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