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Wewaii [24]
3 years ago
11

How many minutes will it take to electroplate 60.1 g of gold by running 5.00 a of current through a solution of au (aq?

Chemistry
2 answers:
Akimi4 [234]3 years ago
8 0

Answer:

It would take 0.1 minutes (approximately 6 seconds)

Explanation:

Applying the Faraday's first law of electrolysis which states that,

    m = ZIt

where m is the mass electroplated, Z is the electrochemical equivalence of the element, I is the current and t is the time taken.

Z of gold = 2.04352g/As

Thus,

t = \frac{m}{ZI}

   = \frac{60.1}{2.04352 *5}

   = 5.882 s

To determine the time in minute, divide by 60;

t = 0.0980minute

t = 0.1 minute

Elden [556K]3 years ago
3 0
For this problem, we use the Faradays law to relate the mass electroplated and the current passed through. We do as follows:

60.1 g (1 mol / 196.67 g) (1 mol e- / 1 mol Au) ( 96500 C / 1 mol e- ) = 29486.25 C

Q = It
29486.25 = 5t
t = 5897.85 s = 98.30 min

Hope this answers the question.
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In a separate experiment beginning from the same initial conditions, including a temperature Ti of 25.0°C, half the number of mo
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Answer:

- 178 ºC

Explanation:

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PV = nRT,

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For the initial conditions :

P₁ V₁ = n₁ R T₁    (1)

and for the final conditions:

P₂V₂= n₂ R T₂    where   n₂ = n₁/2     then    P₂ V₂ = n₁/2 T₂    (2)

Assuming V₂ = V₁ and  dividing (2) by Eqn (1) :

P₂ V₂ = n₁/2 R T₂  / ( n₁ R T₁)      then  P₂ / P₁ = 1/2 T₂ / T₁

4.10 atm / 25.7 atm = 1/2 T₂ / 298 K ⇒ T₂ = 0.16 x 298 x 2 = 95.1 K

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6 0
3 years ago
The total concentration of ions in a 0.75 M solution of HCl is
EastWind [94]
<h3>Answer:</h3>

The total concentration of ions in a 0.75 M solution of HCl is 1.5 M

That is; 0.75 M H⁺ and 0.75 M Cl⁻

<h3>Explanation:</h3>
  • Concentration or molarity is the number of moles of a compound or an ion contained in one liter of solution. It is measured in moles per liter (M).
  • The concentration of ions making a compound is determined by the ratio of moles of the compound and the constituents ions.
  • For instance, HCl dissociates to give H⁺ and Cl⁻

       HCl(aq) → H⁺(aq) + Cl⁻(aq)

  • Therefore, since the mole ratio between HCl and the constituent ions H⁺ and Cl⁻ is 1:1, then 0.75 M of HCl dissociates to give 0.75 M H⁺ and 0.75 m Cl⁻
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