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3 years ago

If y = 12 when x = -5, determine y when x = 2

Mathematics

1 answer:

Jobisdone [24]3 years ago

4 0

Answer:y=-120

Step-by-step explanation:

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Please help

baherus [9]

Answer:

-11/4

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(2-57)/(23-3)

m=-55/20

simplify

m=-11/4

Please mark me as Brainliest if you're satisfied with the answer.

3 0

3 years ago

Sample size: A researcher is trying to decide how many people to survey. Which of the following sample sizes will result in a co

oksian1 [2.3K]

Answer:

Step-by-step explanation:

Given that a researcher is trying to decide how many people to survey.

We have confidence intervals are intervals with middle value as the mean and on either side margin of error.

Confidence interval = Mean ± Margin of error

Thus confidence interval width depends on margin of error.

Margin of error = $Critical value *\frac{\sigma}{\sqrt{n} }$

Thus for the same confidence level and std deviation we find margin of error is inversely proportional to square root of sample size.

Hence for small n we get wide intervals.

So if sample size = 300, the researcher will get wider confidence interval

4 0

4 years ago

I need help with this assignment. This is the last one for the year so I can get my geometry credit! Thank you to anyone who cho

kirill [66]

Answer:

i can help u just give me the work

Step-by-step explanation:

5 0

3 years ago

Find the area and the circumference of the circle with the radius 6yd.

fgiga [73]

Answer:

Step-by-step explanation:

The formula of an area of a circle:

$A=\pi r^2$

The formula of a circumference of a circle:

$C=2\pi r$

<em>r</em><em> - radius</em>

<em />

We have <em>r = 6yd</em>.

Substitute:

$A=\pi(6^2)=36\pi\ yd^2$

$C=2\pi(6)=12\pi\ yd$

If you want round the answers, then use <em>π ≈ 3.14</em>

$A\approx(36)(3.14)=113.04\ yd^2$

$C\approx(12)(3.14)=37.68\ yd$

3 0

4 years ago

The hydrogen ion concentration (h+) in a certain cleaning compound is (h+)=3.2x10^-11 use the formula ph=-log(h+) to find the pH

Furkat [3]

Answer:

The $pH$ of the clean compound is approximately 10.495.

Step-by-step explanation:

If the cleaning ion concentration of the cleaning compound is $[H^{+}] = 3.2\times 10^{-11}$ , then the $pH$ , no unit, of the compound is:

$pH = -\log_{10} [H^{+}]$ (1)

$pH = -\log_{10} (3.2\times 10^{-11})$

$pH = -\log_{10} 3.2 - \log_{10} (10^{-11})$

$pH = -\log_{10} \frac{32}{10} +11$

$pH = -\log_{10} 32 + \log_{10} 10 + 11$

$pH = -\log_{10} 32 +12$

$pH \approx 10.495$

The $pH$ of the clean compound is approximately 10.495.

6 0

3 years ago