Question

The hydrogen ion concentration (h+) in a certain cleaning compound is (h+)=3.2x10^-11 use the formula ph=-log(h+) to find the pH of the clean compound the pH is approximately

Answer 1

Answer:

The $pH$ of the clean compound is approximately 10.495.

Step-by-step explanation:

If the cleaning ion concentration of the cleaning compound is $[H^{+}] = 3.2\times 10^{-11}$, then the $pH$, no unit, of the compound is:

$pH = -\log_{10} [H^{+}]$  (1)

$pH = -\log_{10} (3.2\times 10^{-11})$

$pH = -\log_{10} 3.2 - \log_{10} (10^{-11})$

$pH = -\log_{10} \frac{32}{10} +11$

$pH = -\log_{10} 32 + \log_{10} 10 + 11$

$pH = -\log_{10} 32 +12$

$pH \approx 10.495$

The $pH$ of the clean compound is approximately 10.495.