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4 years ago

Distribute: -3(4x-5)

Mathematics

1 answer:

In-s [12.5K]4 years ago

6 0

The answer is C. You forgot to distribute the -3 and 5 when you chose A. In this case, -3*5=-15.

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Find EXACT area of regular hexagon (keep in radical form)

pickupchik [31]

Answer:

1. $24\sqrt{3}$ 2. $162\sqrt{2}$

Step-by-step explanation:

1. The area of a hexagon is A = $\frac{3\sqrt{3} }{2} a^{2}$

Here our a is 4, so plugging in 4 to our equation gives $\frac{3\sqrt{3} }{2} (4^{2})$ which simplifies to $24\sqrt{3}$

2. The area of an octagon is $2\sqrt{2} r^{2}$

Here our r is 9, so plugging in 9 to our equation gives $2\sqrt{2} (9^{2} )$ which simplifies to $162\sqrt{2}$

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4 years ago

Hello. Can I please have help on this question. It is said that 9.42 is not the answer. There needs to be two answers, help is n

Ymorist [56]

The first one is 9.42 and the 2nd one is 18.84

4 0

3 years ago

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Sal bought 3 CDs for $15.98 each, a computer cable for $39.95, and a case for his MP3 player for $24.99. Sales tax is 7%. To the

Anna35 [415]

Add up and you get 112.88

100/107=112.88/?
107*112.88/100=?

=120.78

5 0

4 years ago

Please help me this is worth alot of points:(

asambeis [7]

SOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOO

I´m sure this was already answered because for me it says it was from a while ago so ima just take tha points

THAMKSSSSSSSSSSSSSSSSSSSSSS

3 0

3 years ago

Ixl geometry help pls !

timurjin [86]

$\bf ~\hspace{5em} \textit{ratio relations of two similar shapes} \\\\ \begin{array}{ccccllll} &\stackrel{\stackrel{ratio}{of~the}}{Sides}&\stackrel{\stackrel{ratio}{of~the}}{Areas}&\stackrel{\stackrel{ratio}{of~the}}{Volumes}\\ \cline{2-4}&\\ \cfrac{\stackrel{similar}{shape}}{\stackrel{similar}{shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array}~\hspace{6em} \cfrac{s}{s}=\cfrac{\sqrt{Area}}{\sqrt{Area}}=\cfrac{\sqrt[3]{Volume}}{\sqrt[3]{Volume}} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \cfrac{small}{large}\qquad \qquad \stackrel{sides}{\cfrac{3}{7}} ~~ = ~~ \stackrel{areas}{\sqrt{\cfrac{A_1}{98}}}\implies \left( \cfrac{3}{7} \right)^2 = \cfrac{A_1}{98}\implies \cfrac{3^2}{7^2}= \cfrac{A_1}{98} \\\\\\ \cfrac{9}{49}= \cfrac{A_1}{98}\implies 882 = 49A_1\implies \cfrac{882}{49}=A_1\implies 18=A_1$

3 0

3 years ago

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