Answer:
1 is 0.6 and 2 is 612 3 is 39.2 and 4 is -3 and 5 is 9/4 or (2 1/4)
Step-by-step explanation:
:)
Lets write each part, the total will be x:
(1/10)x = Europe
3200 = Asia
x - <span>(1/10)x - 3200 = Africa
Europe + Asia = </span><span>(1/10)x + 3200 = x/10 + 3200
= (320x + 1)/3200
that would be expressed as a fraction, and depends on the total of coins, x</span>
The image is decomposed as follows: H1 and H2. Where original graph is Hx.
<h3>Are the images (attached) valid decompositions of the original graph?</h3>
- Yes, they are because, H1 and H1 are both sub-graphs of Hx; also
- H1 ∪ H2 = Hx
- They have no edges in common.
Hence, {H1 , H2} are valid decomposition of G.
<h3>What is a Graph Decomposition?</h3>
A decomposition of a graph Hx is a set of edge-disjoints sub graphs of H, H1, H2, ......Hn, such that UHi = Hx
See the attached for the Image Hx - Pre decomposed and the image after the graph decomposition.
Learn more about decomposition:
brainly.com/question/27883280
#SPJ1
Answer:
B
Step-by-step explanation:
Its the only odd number
Answer:
<em>0</em> is the probability that a randomly selected student plays both a stringed and a brass instrument.
Step-by-step explanation:
Given that:
Number of students who play stringed instruments, N(A) = 15
Number of students who play brass instruments, N(B) = 20
Number of students who play neither, N(
)' = 5
<u>To find:</u>
The probability that a randomly selected students plays both = ?
<u>Solution:</u>
Total Number of students = N(A)+N(B)+N(
)' =15 + 20 + 5 = 40
(As there is no student common in both the instruments we can simply add the three values to find the total number of students)
As per the venn diagram, no student plays both the instruments i.e.

Formula for probability of an event E can be observed as:


So, <em>0</em> is the probability that a randomly selected student plays both a stringed and a brass instrument.