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dolphi86 [110]
2 years ago
15

Find the equation of line parallel to y=-2x+1 and passing through the point (2,4)

Mathematics
1 answer:
SOVA2 [1]2 years ago
5 0

Answer:

y=-2x+8

Step-by-step explanation:

Hi there!

<u>What we need to know:</u>

  • Linear equations are typically organized in slope-intercept form: y=mx+b where m is the slope and b is the y-intercept (the value of y when x is 0)
  • Parallel lines always have the same slopes

<u>1) Determine the slope (m)</u>

y=-2x+1

The given line has a slope of -2. Because parallel lines always have equal slopes, we know that the line parallel to this would also have a slope of -2. Plug this into y=mx+b:

y=-2x+b

<u>2) Determine the y-intercept (b)</u>

y=-2x+b

Plug in the given point (2,4) to solve for b

4=-2(2)+b\\4=-4+b

Add 4 to both sides to isolate b

4+4=-4+b+4\\8=b

Therefore, the y-intercept of the line is 8. Plug this back into y=-2x+b:

y=-2x+8

I hope this helps!

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