Answer:
y = (x/(1-x))√(1-x²)
Step-by-step explanation:
The equation can be translated to rectangular coordinates by using the relationships between polar and rectangular coordinates:
x = r·cos(θ)
y = r·sin(θ)
x² +y² = r²
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r = sec(θ) -2cos(θ)
r·cos(θ) = 1 -2cos(θ)² . . . . . . . . multiply by cos(θ)
r²·r·cos(θ) = r² -2r²·cos(θ)² . . . multiply by r²
(x² +y²)x = x² +y² -2x² . . . . . . . substitute rectangular relations
x²(x +1) = y²(1 -x) . . . . . . . . . . . subtract xy²-x², factor
y² = x²(1 +x)/(1 -x) = x²(1 -x²)/(1 -x)² . . . . multiply by (1-x)/(1-x)

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The attached graph shows the equivalence of the polar and rectangular forms.
8775
/ \
3 2925
/ \
3 975
/ \
3 325
/ \
5 65
/ \
5 13
/ \
13 1
Prime Factors: 3, 3, 3, 5, 5, 13
Answer:
4
Step-by-step explanation:
Add each sample separately
A.17 B. 47 C. 39 D. 52 E. 45
Then you add them all together which totals 200 sick days
We know that they surveyed 5 schools and 10 students at random from each one. So we want to know the mean of sick days the students took not the schools in all.
So we divide 200/50
And get a mean of 4.
So each student took an average of 4 sick days each in the country.
The LCD is 30.
Think of it this way. You and I are on an assembly line checking i-pads. Your job is to quality check every 6th one and my job is to check every 10th one.
Here are the ones you will check:
6, 12, 18, 24, 30 and so on
Here are the ones I will check
10, 20 30 and so on.
Notice the first one we both check? #30 - that is the LCD of 6 and 10