What is the y-intercept of the below equation? y = 7x-3.5

Mathematics

1 answer:

Ilya [14]3 years ago

3 0

Answer:

-3.5

Step-by-step explanation:

y=mx+b

b is the y intercept

You might be interested in

“use synthetic method to find the quotient”

guapka [62]

Answer:

1) $2x^{4} -x^{3} +2x^{2} -4x+5+\frac{6}{x+2}$

2) $5x^{3}+15x^{2} +45x+151+\frac{474}{x-3}$

Step-by-step explanation:

7 0

3 years ago

How to subtract an integer

Evgesh-ka [11]

If both signs are positive, the answer will be positive. Example: 14 - (-6) = 14 + 6 = 20.If both signs are negative, the answer will be negative. ... If the signs are different subtract the smaller absolute value from the larger absolute value.Is what I found

3 0

3 years ago

Read 2 more answers

Choose the correct graph of the following condition. {(x, y) : x = 4) o [(x,y): y = 4)

Studentka2010 [4]

Answer:

There is no solution

Step-by-step explanation:

7 0

3 years ago

The scale drawing of a rectangular office measures 5.3 cm by 8 cm. A scale factor of 72 is used to create the actual office. Wha

Musya8 [376]

Each length is 72 times longer so the actual dimensions are 381.6cm by 576 cm

5 0

3 years ago

A mass weighing 3 lb stretches a spring 3 in. If the mass is pushed upward, contracting the spring a distance of 1 in and then s

Bas_tet [7]

Answer:

Step-by-step explanation:

$m=\frac{3}{32}\\ \gamma =0\text{ damping constant.}\\ k=\frac{3}{\frac{1}{4}}=12\\ F(t)=0\\ \text{so equation of motion is }\\ mu''+\gamma u'+ku=F(t)\\ \frac{3u''}{32}+12u=0\\ u''+128u=0\\ \text{and initial conditions are}\\ u(0)=-\frac{1}{12}\\ u'(0)=2\\ u''+128u=0\\ \text{characterstic equation is}\\ r^2+128=0\\ \text{roots are }\\ r=\pm 8\sqrt{2}i\\ \text{therefore general solution is}\\ u(t)=A\cos8\sqrt{2}t+Bsin8\sqrt{2}t\\ \text{using initial conditions we get}\\ A=-\frac{1}{12}\\ B=\frac{\sqrt{2}}{8}\\ \text{therefore solution is }\\ u(t)=-\frac{1}{12}\cos8\sqrt{2}t+\frac{\sqrt{2}}{8}\sin8\sqrt{2}t\\
{hence}\\R=\sqrt{\frac{11}{288}}\\\\\sigma=\pi - \tan^{-1}\frac{1}{\sqrt{2}}\\\\\omega_0=8\sqrt{2}\\T=\frac{4}{4\sqrt{2}}$

3 0

3 years ago