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Ilia_Sergeevich [38]
3 years ago
6

The sum of two number is 10. the difference between the numbers is 4. what are the two numbers.

Mathematics
1 answer:
dolphi86 [110]3 years ago
3 0
Your answer is 7 and 3.
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Plz help I need to know which equation is correct
denis-greek [22]
Its C 10d+ 5n I know it doesnt tell you numbers but a dime is 10 cents and a nickel is 5 cents which obviously would help you find the answer but you dont need the answer just how they would make it an problem so yea, its C 10d + 5n
5 0
3 years ago
Find the area of the regular hexagon if a side is 30m.
vovangra [49]
The answer is A.
Hope it helps
4 0
3 years ago
Read 2 more answers
A=10t+0 find the y intercept
irinina [24]

Answer:

0

Step-by-step explanation:

The y intercept is the constant in this equation, as in the only number unaccompanied or affected by a variable. In this case, assuming y is a and x is t, the y intercept is 0. You can test this by plugging in y=10x+0 into a graphing calculator. The y intercept is where x equals 0, and so if you plug in 0 for x, the result (in this case 0) is the y intercept. Hope this helps, brainliest is always appreciated and have an amazing day!

3 0
3 years ago
If a is a solution of abs(x+3)>4, then is a also a solution of x+3>4?
Alexandra [31]

Answer:

Yes

Step-by-step explanation:

After solving for the two values of a, the second inequality gives a value inside the range of the first inequality.

7 0
3 years ago
A 90 percent confidence interval is to be created to estimate the proportion of television viewers in a certain area who favor m
Dominik [7]

Answer:

This means that the first interval, with 9000 viewers, is 3 times as narrower as the second interval, with 1000 viewers.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The width of the interval is:

W = 2z\sqrt{\frac{\pi(1-\pi)}{n}}

In this sample:

Two 90% intervals, with different lenghts. So both have the same values for z an \pi

Interval A:

9000 viewers.

So the width is

W_{A} = 2z\sqrt{\frac{\pi(1-\pi)}{9000}}

Interval B:

100 viewers

So the width is

W_{B} = 2z\sqrt{\frac{\pi(1-\pi)}{1000}}

Relationship between the widths:

R = \frac{W_{A}}{W_{B}} = \frac{2z\sqrt{\frac{\pi(1-\pi)}{9000}}}{2z\sqrt{\frac{\pi(1-\pi)}{1000}}} = \frac{\sqrt{1000}}{\sqrt{9000}} = \frac{\sqrt{1}}{\sqrt{9}} = \frac{1}{3}

This means that the first interval, with 9000 viewers, is 3 times as narrower as the second interval, with 1000 viewers.

8 0
4 years ago
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